5

我有 2 张桌子

部门

ID  Dept
---------
1   HR
2   Accts
3   IT

员工

ID Name     Depts
-------------------
1  Kevin     2,1
2  Michelle  1
3  Troy      1,3
4  Rheesa    2,3,1

我正在寻找带有 SQL 查询的如下输出。

员工部门 

ID Name      Depts
-------------------------
 1 Kevin     Accts,HR
 2 Michelle  HR
 3 Troy      HR,IT
 4 Rheesa    Accts,IT,HR

我尝试了以下方法，将 s 与 depts 连接，但只为每个 depts 生成一行。如何使用查询获得上述结果？

select 
    name, depts, dept 
from 
    employee
CROSS APPLY  
    dbo.split_list(employee.depts ,',') split
inner join 
    dbo.department on  depts= split.value
order by 
    name
4

5 回答 5

7 
DECLARE @Departments TABLE 
(
  ID INT PRIMARY KEY, 
  Dept VARCHAR(32) NOT NULL UNIQUE
);

DECLARE @Employees TABLE
(
  ID INT PRIMARY KEY,
  Name NVARCHAR(64) NOT NULL,
  Depts VARCHAR(255) NOT NULL
);

INSERT @Departments VALUES 
  (1,'HR'),  (2,'Accts'),  (3,'IT');

INSERT @Employees VALUES
  (1,'Kevin','2,1'), (2,'Michelle','1'),
  (3,'Troy','1,3'),  (4,'Rheesa','2,3,1');

SELECT ID, Name, Depts = STUFF((SELECT ',' + d.Dept 
    FROM @Departments AS d
    INNER JOIN @Employees AS ei
    ON ',' + ei.Depts + ',' LIKE '%,' + CONVERT(VARCHAR(12), d.id) + ',%'
    WHERE ei.ID = e.ID
    ORDER BY Dept
    FOR XML PATH, 
    TYPE).value(N'/text().[1]', N'nvarchar(max)'), 1, 1, N'')
FROM @Employees AS e
ORDER BY ID;

结果与您所需的结果不太匹配，因为排序是确定性的（按部门名称排序）：

ID      Name        Depts
----    --------    ----
1       Kevin       Accts,HR
2       Michelle    HR
3       Troy        HR,IT
4       Rheesa      Accts,HR,IT

如果您希望它们按逗号分隔列表中的外观排序，只需更改：

ORDER BY Dept

至：

ORDER BY CHARINDEX( ',' + CONVERT(VARCHAR(12), d.id) + ',', ',' + ei.Depts + ',')

结果：

ID      Name        Depts
----    --------    ----
1       Kevin       Accts,HR
2       Michelle    HR
3       Troy        HR,IT
4       Rheesa      Accts,IT,HR -- this is the only one affected as it turns out

但是，实际上，您应该规范化您的数据库。这绝对是一场噩梦。

于 2013-01-30T20:26:01.280 回答
3

除了如何存储数据之外，让我尝试为您提供帮助。

好吧，你在这里问了很多问题。首先，要拆分数据，您可以将其格式化为 XML 并使用 CROSS APPLY——我不久前看到的不需要内置函数的技巧。

这会将您的逗号分隔字符串转换为字符串列表。然后，您可以使用 FOR XML 将它们重新组合在一起。

试一试：

SELECT
   E.Id, 
   E.Name, 
   STUFF(
        (
        SELECT ',' +  D.Department AS [text()]
        FROM  (
           SELECT A.[id],  
             Split.a.value('.', 'VARCHAR(100)') AS DeptId  
           FROM  
              (SELECT [id],  
                 CAST ('<M>' + REPLACE(Depts, ',', '</M><M>') + '</M>' AS XML) AS String  
              FROM  Employee
          ) AS A 
        CROSS APPLY String.nodes ('/M') AS Split(a)) A 
        JOIN Departments D ON A.DeptId = D.Id
        WHERE E.Id = A.Id
        FOR XML PATH('')
        ), 1, 1, '') AS Departments
FROM Employee E

这是SQL Fiddle。

祝你好运。

于 2013-01-30T20:06:21.890 回答
2

您还可以使用递归 CTE 来拆分数据，然后使用FOR XML PATH将行连接成一行：

;with cte (id, name, deptid, depts) as
(
  select id, name,
    cast(left(depts, charindex(',',depts+',')-1) as varchar(50)) deptid,
         stuff(depts, 1, charindex(',',depts+','), '') depts
  from employee
  union all
  select id, name,
    cast(left(depts, charindex(',',depts+',')-1) as varchar(50)) deptid,
    stuff(depts, 1, charindex(',',depts+','), '') depts
  from cte
  where depts > ''
) 
select e.id, e.name,
  stuff((
         select distinct ', '+ d.dept
         from cte c
         inner join departments d
            on c.deptid = d.id
         where e.id = c.id
         for XML path('')),1,1,'') Depts
from employee e

请参阅带有演示的 SQL Fiddle

结果：

| ID |     NAME |          DEPTS |
----------------------------------
|  1 |    Kevin |      Accts, HR |
|  2 | Michelle |             HR |
|  3 |     Troy |         HR, IT |
|  4 |   Rheesa |  Accts, HR, IT |
于 2013-01-30T20:34:25.000 回答
1

您还可以将选项与动态管理功能sys.dm_fts_parser 一起
使用 在脚本执行之前，您需要检查全文组件是否已安装：

SELECT FULLTEXTSERVICEPROPERTY ('IsFulltextInstalled')

0 = 未安装全文。1 = 已安装全文。NULL = 无效输入或错误。

如果 0 = 全文未安装，那么这篇文章对您来说是必要的如何在 sql server 2008 上安装全文？

SELECT b.ID, b.Name, STUFF((
SELECT ',' + d.Dept
FROM Employees e 
  JOIN Departments d ON d.ID IN(
                                SELECT display_term 
                                FROM sys.dm_fts_parser('"' + e.Depts + '"', 1033, NULL, 0) 
                                WHERE display_term NOT LIKE 'nn%'
                                )
WHERE b.ID = e.ID
ORDER BY d.Dept
FOR XML PATH('')), 1, 1, '') AS Depts
FROM Employees b

或者

SELECT e.ID, e.Name, 
 (
  STUFF((
  SELECT ',' + Dept
  FROM sys.dm_fts_parser('"' + e.Depts + '"', 1033, NULL, 0) p JOIN Departments d ON p.display_term = d.ID
  WHERE display_term NOT LIKE 'nn%'
  FOR XML PATH('')), 1, 1, '')
  ) AS Depts
 FROM Employees e
于 2013-01-30T21:51:53.023 回答
0

编写一个用于拆分逗号分隔值的函数。我写了 dbo.split

select * from dbo.split('1,2,3',',') 将返回 - Data 1 2 3

SELECT tact.ActivityID,CONVERT(NVARCHAR(20),tact.createddate,103) AS CallDate,
ActivityOriginatedByPartyID , (ISNULL(p.firstname,'')+' '+ISNULL(p.lastname,'')) AS PartnerName,
u.UserName AS PSTName, ccv.codevalue AS CallType
**, ccv1.codevalue AS CallContext**
,tact.ActivityNote AS CallTrackerNote,
(CONVERT(VARCHAR(20),tact.ActivityTimeSpend) + ' Min') AS CallDuration
FROM txn_activity tact (NOLOCK)
INNER JOIN TXN_Party p (NOLOCK) ON p.PartyID = tact.ActivityOriginatedByPartyID 
INNER JOIN TXN_User u (NOLOCK) ON u.userid = tact.createdby
INNER JOIN CFG_CodeValue ccv (NOLOCK) ON ccv.codevalueid = tact.ActivityTypeID
--INNER JOIN CFG_CodeValue ccv1 (NOLOCK) ON ccv1.codevalueid = tact.ActivityContext

**CROSS APPLY  
    dbo.split(tact.ActivityContext,',') split
inner join 
    dbo.CFG_CodeValue ccv1 (NOLOCK) ON ccv1.codevalueid = split.data**
于 2015-03-05T05:55:49.353 回答