0

我有一个 varchar 变量,其内容如下:'123,12,7654321,9998...'。我在 Oracle 10gR2 工作。如何实现以下输出格式?:

------
123
12
7654321
9998
...
------

谢谢!

4

3 回答 3

1

试试这个

SELECT EXTRACTVALUE(COLUMN_VALUE,'text()') VALS 
FROM XMLTABLE('123,12,7654321,9998');

或者

SELECT COLUMN_VALUE VALS FROM XMLTABLE('123,12,7654321,9998');
于 2013-01-30T19:07:10.817 回答
0

这是一种使用方法connect

with str as (select '123,12,7654321,9998' as val from dual)
select cast(regexp_substr(val,'[^,]+', 1, level) as int)
from str
connect by cast(regexp_substr(val, '[^,]+', 1, level) as int) is not null;

我承认我改编自这篇文章。您要做的通常是放入一个名为“split”的函数中。

于 2013-01-30T19:10:16.443 回答
0

试试这个 :

/* Formatted on 1/30/2013 1:24:07 PM (QP5 v5.227.12220.39724) */
WITH val AS (SELECT '123,12,7654321,9998' txt FROM DUAL)
SELECT REGEXP_SUBSTR (txt,
              '[0-9]+|[a-z]+|[A-Z]+',
              1,
              lvl)
  FROM (SELECT txt,
           LEVEL lvl
      FROM val
    CONNECT BY LEVEL <=   LENGTH (txt)
                - LENGTH (REPLACE (txt,
                           ','))
                + 1)
于 2013-01-30T19:25:53.723 回答