0

我试图弄清楚为什么我在这里收到 404 错误,但我就是看不到它。

这是我的 web.xml:

<servlet>
    <servlet-name>ep</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>ep</servlet-name>
    <url-pattern>/ep/*</url-pattern>
</servlet-mapping>

这是我的 ep-servlet.xml(只有“beans”标签围绕以下代码):

<mvc:annotation-driven />

<context:component-scan base-package="server.service2">
</context:component-scan>

这是课程本身:

package server.service2;
....

@Controller
@RequestMapping("/user")
public class LoginService
{
    @RequestMapping(value = "/check/{username}", method = RequestMethod.GET)
    public void checkUsername(@PathVariable("username") String username)
    {
    }
}

我用浏览器访问的网址是:

http://<server>:<correct-port>/ep/user/check/username

它返回一个 404!谁能发现我在这里做错了什么?

4

1 回答 1

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嗨@Amorgos,您可以将文件订购到下一个:

web.xml

<servlet>
  <servlet-name>ep</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
  <servlet-name>ep</servlet-name>
  <url-pattern>/</url-pattern>
</servlet-mapping>

<!-- Add Support for Spring -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
    <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<listener>
    <listener-class>org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>

ep-servlet.xml

<context:annotation-config />

<context:component-scan base-package="server.service2" />

<beans:bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" />

<!-- Register the bean -->
<beans:bean class="server.service2.LoginService" />

我希望这些有帮助:)

于 2013-01-31T05:09:42.617 回答