5
SELECT  cm.commenter_id,
        cm.comment,
        m.id,
        (
            SELECT COUNT(*) AS r_count
            FROM comments
            GROUP BY comments.commenter_id
        ) AS count,
        m.display_name
FROM    comments cm
        INNER JOIN members m
            ON cm.commenter_id = m.id

从这个查询中,我想获得评论数最多的人的 display_name。任何指导表示赞赏。

4

2 回答 2

3
SELECT  m.id, m.display_name, COUNT(*) totalComments
FROM    comments cm
        INNER JOIN members m
            ON cm.commenter_id = m.id
GROUP   BY m.id, m.display_name
HAVING  COUNT(*) =
    (
        SELECT  COUNT(*) totalCount
        FROM    Comments
        GROUP   BY  commenter_id
        ORDER   BY totalCount DESC
        LIMIT 1
    )
于 2013-01-30T14:54:26.233 回答
0

我认为最简单的方法就是对查询进行排序并取第一行:

SELECT  cm.commenter_id,
        cm.comment,
        m.id,
        (
            SELECT COUNT(*) AS r_count
            FROM comments
            GROUP BY comments.commenter_id
        ) AS count,
        m.display_name
FROM    comments cm
        INNER JOIN members m
            ON cm.commenter_id = m.id
order by count desc
limit 1
于 2013-01-30T18:36:47.853 回答