SELECT cm.commenter_id,
cm.comment,
m.id,
(
SELECT COUNT(*) AS r_count
FROM comments
GROUP BY comments.commenter_id
) AS count,
m.display_name
FROM comments cm
INNER JOIN members m
ON cm.commenter_id = m.id
从这个查询中,我想获得评论数最多的人的 display_name。任何指导表示赞赏。