我正在我的组模型上测试一种方法。它依赖于通过工厂创建一些徽章类型。
这是代码
it "add itself to badges with method add_to_badgetypes" do
badge = FactoryGirl.create(:badgetype)
old_badge_ids = badge.group_ids.split(",")
badge2 = FactoryGirl.create(:badgetype, :group_ids => "3,4,5")
group.add_to_badgetypes(badge.id, badge2.id)
expect( badge.group_ids ).to eq( old_badge_ids.push(group.id).join(",") )
end
'
badge.group_ids' 之前是“200, 300”,之后应该是“200,300,#{group.id}”。当我跟踪日志时,我看到了这个:
` Badgetype Load (0.5ms) SELECT group_ids FROM `badge_types` WHERE `badge_types`.`id` = 40 LIMIT 1
(0.2ms) SAVEPOINT active_record_1
(0.3ms) UPDATE `badge_types` SET `group_ids` = '200,300,15' WHERE `badge_types`.`id` IS NULL
(0.2ms) RELEASE SAVEPOINT active_record_1
Badgetype Load (0.4ms) SELECT group_ids FROM `badge_types` WHERE `badge_types`.`id` = 41 LIMIT 1
(0.1ms) SAVEPOINT active_record_1
(0.3ms) UPDATE `badge_types` SET `group_ids` = '3,4,5,15' WHERE `badge_types`.`id` IS NULL
(0.1ms) RELEASE SAVEPOINT active_record_1
(0.3ms) ROLLBACK
(0.1ms) BEGIN
`
所以它成功更新了 group_ids,但由于某种原因测试失败,如果我 pp badge.group_ids 我得到原始值(200,300),而不是更新后的值。
我认为这与“SAVEAPOINT active_record_1”有关,然后是 UPDATE,然后是 RELEASE SAVEPOINT。如果是这样,为什么?
我怎样才能让这个规范通过,因为它似乎都在数据库中搞砸了,而不是方法。
谢谢
编辑
通过在控制台中玩耍发现了一些更有趣的信息。如果我创建一个工厂并为其分配一行:
g = FactoryGirl.create(:group)
然后运行:
g.add_to_badgetype(1,2)
我得到这个 SQL
1.9.3-p286 :080 > g.add_to_badgetypes(1, 2)
Badgetype Load (0.5ms) SELECT group_ids FROM `badge_types` WHERE `badge_types`.`id` = 1 LIMIT 1
(0.1ms) BEGIN
(0.2ms) UPDATE `badge_types` SET `group_ids` = 'test,8,9,10' WHERE `badge_types`.`id` IS NULL
(0.1ms) COMMIT
Badgetype Load (0.3ms) SELECT group_ids FROM `badge_types` WHERE `badge_types`.`id` = 2 LIMIT 1
(0.1ms) BEGIN
(0.2ms) UPDATE `badge_types` SET `group_ids` = '200,300,8,9,10' WHERE `badge_types`.`id` IS NULL
(0.1ms) COMMIT
=> [1, 2]
注意奇怪的 UPDATE 语句“WHERE badge_types.id IS NULL”
如果在创建工厂之后,我将它重新分配给一个变量,然后运行相同的命令,它可以找到:
1.9.3-p286 :081 > g = Group.last
Group Load (0.5ms) SELECT `groups`.* FROM `groups` ORDER BY `groups`.`id` DESC LIMIT 1
=> #<Group id: 10, group_name: "Test Group", short_name: "test_group", enrollment: false, kiosk: false, landing: 0, ro_landing: 0>
1.9.3-p286 :082 > g.add_to_badgetypes(1, 2)
Badgetype Load (0.6ms) SELECT `badge_types`.* FROM `badge_types` WHERE `badge_types`.`id` = 1 LIMIT 1
(0.1ms) BEGIN
(0.4ms) UPDATE `badge_types` SET `group_ids` = 'test,8,9,10' WHERE `badge_types`.`id` = 1
(0.2ms) COMMIT
Badgetype Load (0.4ms) SELECT `badge_types`.* FROM `badge_types` WHERE `badge_types`.`id` = 2 LIMIT 1
(0.1ms) BEGIN
(0.4ms) UPDATE `badge_types` SET `group_ids` = '200,300,8,9,10' WHERE `badge_types`.`id` = 2
(0.2ms) COMMIT
=> [1, 2]
显然,作为工厂的组导致 SQL 更新语句查找 NULL 的 id。
有任何想法吗?