sql - 表之间的 Ruby 条件

Question

我有 2 张桌子：

反馈 : faceid (as int), Poolid (as int), deleted (as boolean)

池：id（作为 int），取消（作为布尔值）

两个表之间没有数据库集成，除了某些行包含相同的值（pool.id 可以等于 feedback.poolid）。

如果我在哪里用 SQL 编写查询，它将类似于：

SELECT Pool.* , Feedback.* FROM Pool, Feedback WHERE faceid = params[:faceid] 
and deleted = 'f' and (Pool.id = Feedback.poolid and Pool.cancel = 'f') 

实现它的最佳（和参数化）方法是什么？

Answer 1

我认为以下将起作用：

 Pool.find_by_sql("select * from pools,feedbacks where pools.id = feedbacks.pool_id and cancelled = false and deleted = false and faceid = #{params[:faceid]}")

Answer 2

@host = Pool.find_by_sql("SELECT pools.* FROM pools, feedbacks WHERE (pools.id = feedbacks.poolid) AND (pools.cancel = 'f') AND (feedbacks.deleted = 'f') AND (feedbacks.faceid = #{params[:faceid]})")

谢谢你们