sql-server - SQL 2 语句创建一个 3 语句，并将 2 连接在一起

Question

这是我的 SQL 语句：

SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30

Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr

第一个将返回此数据：

repnr daystotal
1000  100
1001  90
1003  91

第二个声明：

repnr extern
900   100
901   102
1000  21
1003  23

我想要的是 repnr （这是一个 ID）匹配的地方，我想减去 to 值，所以我看起来像这样：

repnr result
1000  79
1003  68

我如何为 MSSQL 执行此操作。

Answer 1

SELECT q1.repnr, q1.daystotal - q2.extern as [result]
FROM
(
SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30
)q1
INNER JOIN 
(
Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr
)q2 ON q1.repnr = q2.repnr

Answer 2

将您的查询设置为子查询并加入您的密钥，您应该一切顺利。

select repnr, DaysTotal - extern as result from (SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30) a inner join (Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr) b on a.repnr = b.repnr

Answer 3

SELECT a.repnr, ABS(A.daystotal - b.extern) AS result
FROM(
SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30
)A
JOIN(
Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr
)B
ON A.repnr = b.repnr