我编写了一个函数，它使用以下方法从文本中提取日期strtotime()：
function parse_date_tokens($tokens) {
# only try to extract a date if we have 2 or more tokens
if(!is_array($tokens) || count($tokens) < 2) return false;
return strtotime(implode(" ", $tokens));
}
function extract_dates($text) {
static $patterns = Array(
'/^[0-9]+(st|nd|rd|th|)?$/i', # day
'/^(Jan(uary)?|Feb(ruary)?|Mar(ch)?|etc)$/i', # month
'/^20[0-9]{2}$/', # year
'/^of$/' #words
);
# defines which of the above patterns aren't actually part of a date
static $drop_patterns = Array(
false,
false,
false,
true
);
$tokens = Array();
$result = Array();
$text = str_word_count($text, 1, '0123456789'); # get all words in text
# iterate words and search for matching patterns
foreach($text as $word) {
$found = false;
foreach($patterns as $key => $pattern) {
if(preg_match($pattern, $word)) {
if(!$drop_patterns[$key]) {
$tokens[] = $word;
}
$found = true;
break;
}
}
if(!$found) {
$result[] = parse_date_tokens($tokens);
$tokens = Array();
}
}
$result[] = parse_date_tokens($tokens);
return array_filter($result);
}
# test
$texts = Array(
"The focus of the seminar, on Saturday 2nd February 2013 will be [...]",
"Valentines Special @ The Radisson, Feb 14th",
"On Friday the 15th of February, a special Hollywood themed [...]",
"Symposium on Childhood Play on Friday, February 8th",
"Hosting a craft workshop March 9th - 11th in the old [...]"
);
$dates = extract_dates(implode(" ", $texts));
echo "Dates: \n";
foreach($dates as $date) {
echo " " . date('d.m.Y H:i:s', $date) . "\n";
}
这输出：
Dates:
02.02.2013 00:00:00
14.02.2013 00:00:00
15.02.2013 00:00:00
08.02.2013 00:00:00
09.03.2013 00:00:00
这个解决方案可能并不完美，当然也有缺陷，但它是解决您问题的一个非常简单的解决方案。