| uploadedby | uploaddate |
Gracey Vinas | 2012-04-20 20:16:00
Gracey Vinas | 2012-04-20 20:25:00
Gracey Vinas | 2012-04-20 20:35:00
Gracey Vinas | 2012-04-20 20:39:00
Gracey Vinas | 2012-04-20 22:07:00
Gracey Vinas | 2012-04-21 00:04:00
Gracey Vinas | 2012-04-21 01:14:00
Gracey Vinas | 2012-04-23 17:56:00
Gracey Vinas | 2012-04-23 18:06:00
Gracey Vinas | 2012-04-23 18:21:00
Gracey Vinas | 2012-04-23 19:04:00
Gracey Vinas | 2012-04-23 19:11:00
Gracey Vinas | 2012-04-23 19:24:00
Gracey Vinas | 2012-04-23 20:08:00
Gracey Vinas | 2012-04-23 20:22:00
Gracey Vinas | 2012-04-23 21:00:00
Gracey Vinas | 2012-04-23 22:04:00
Gracey Vinas | 2012-04-23 22:17:00
Gracey Vinas | 2012-04-23 22:29:00
Gracey Vinas | 2012-04-23 23:02:00
Gracey Vinas | 2012-04-23 23:48:00
Gracey Vinas | 2012-04-24 00:23:00
Gracey Vinas | 2012-04-24 01:54:00
Gracey Vinas | 2012-04-24 17:13:00
Gracey Vinas | 2012-04-24 17:32:00
Gracey Vinas | 2012-04-24 17:38:00
Gracey Vinas | 2012-04-24 17:45:00
Gracey Vinas | 2012-04-24 17:54:00
如何在 msql 中按日期获取每次上传的平均经过时间。例如(2012 年 4 月 20 日每次上传的平均经过时间为(第 1 行和第 2 行的时间差(9 分钟)+第 2 行和第 3 行的时间差(10 分钟)+第 3 行和第 3 行的时间差) 4(4 分钟)+ 第 4 行和第 5 行的时间差(92 分钟)/4 = 平均经过时间为 28.75 分钟。