8

请帮助我在短时间内学习 google-apps-script。我想通过从存储在我的电子表格中的数据生成的 url 从远程站点下载文件。

例如，我有 2 个参数：

Cell1 = val1, val2, ... valN
Cell2 = val21, val22, ...  val2N

我将字符串从单元格数据拆分为数组，然后生成 URL。例如：http://mysite.com/files/file.val1.val22.zip 比我需要从此链接下载文件...

我可以自动执行此过程吗？

4

3 回答 3

7

此示例函数将检索您的 zip 文件，并将其放入您的 Google Drive 文件夹中的“StackOverflow”文件夹中。您也可以从此gist下载更完整的版本。

function getFile(fileURL) {
  // see https://developers.google.com/apps-script/class_urlfetchapp
  var response = UrlFetchApp.fetch(fileURL);
  var fileBlob = response.getBlob()
  var folder = DocsList.getFolder('StackOverflow');
  var result = folder.createFile(fileBlob);
  debugger;  // Stop to observe if in debugger
}

例如：

getFile( "http://mysite.com/files/file.val1.val22.zip" );

请注意，您本身无法下载，因为您无法从应用程序脚本访问 PC 的资源（例如文件系统）。该文件仍在“云”中......在这种情况下，它已从它所在的网站复制到 Google Drive。但是，如果您正在运行 Drive 应用程序，该文件现在将同步到您的 PC。

于 2013-01-29T01:28:27.803 回答
1

是的你可以。
希望下面的代码可以解决您的问题：

//Declare function
function downloadFile() {
  //Getting url,existing name and new name for image from the sheet in 
  //variable url, name and new_name respectively
  var sh = SpreadsheetApp.getActiveSheet();
  var row = sh.getLastRow();
  Logger.log(row);
  for (var i = 2; i <= row; i++) {

    var url = sh.getRange(i, 10).getValue();
    Logger.log(url);
    var name = sh.getRange(i, 13).getValue();
    var new_name = sh.getRange(i, 4).getValue();
    //Creating authentication token for downloading image, it may not be //required if image can be downloaded without login into
    var user = "***************";
    var password = "************";
    var headers = {
      "Accept": "application/xml",
      "Content-Type": "application/xml",
      "Authorization": "Basic " + Utilities.base64Encode(user + ":" + password)
    };
    //defining method to download file
    var options = {
      "method": "get",
      "headers": headers
    };
    //Getting folder name where to store downloaded image
    var folders = DriveApp.getFoldersByName('test');
    while (folders.hasNext()) {
      var folder = folders.next();
      Logger.log(folder.getName());
    }
    //Getting response on hit of url using downloading method defined //earlier storing in Blob
    var response = UrlFetchApp.fetch(url, options).getBlob();
    //Creating image in folder defined with response in blob and logging same file //in log to check, if required
    var file = folder.createFile(response);
    Logger.log(file);

    //renaming image
    var images = folder.getFiles();
    while (images.hasNext()) {
      var image = images.next();
      file.setName(new_name);
      Logger.log(image.getName());
    }
  }
}
//Hope you get it now
于 2017-05-18T19:33:39.203 回答
1

它对我有用。

function downloadFile() {
  var url = "https://raw.githubusercontent.com/hoat23/VisionArtificialAndImageProcessing/master/bin/utils_imgprocessing.py"
  Logger.log(url);
  var response = UrlFetchApp.fetch(url);
  var text = response.getContentText()
  var newFile = DriveApp.createFile('testfilegoogle.txt',text);
  debugger;  // Stop to observe if in debugger
}
//Hope you get it now
于 2020-07-18T07:25:22.030 回答