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我正在尝试访问显示我的 android 应用程序内容的 json。FileNotFound 异常在 Android 4.0.4 中抛出，但 json 可以在 Android 2.3.3 中访问。也可以使用相同的 url 从浏览器访问 json。代码有什么问题？任何人都可以帮助我解决这个问题。

我正在使用下面的代码：

url = new URL("http://www.dynamiskdesign.se/ipromotionnew/json/148.json");

HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("GET");
httpURLConnection.setDoOutput(true);
httpURLConnection.connect();

InputStream input = httpURLConnection.getInputStream();

if (input != null) {
    writer = new StringWriter();
    char[] buffer = new char[1024];
    Reader reader = new BufferedReader(new InputStreamReader(input, "UTF-8"));
    int n;
    while ((n = reader.read(buffer)) != -1) {
        writer.write(buffer, 0, n);
    }
    input.close();
}

String jsontext = writer.toString();
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1 回答 1

1

这是因为网络和线程的结合。
该页面上也有说明（链接）。我也有这个，看看这个答案： httpclient (phpmyadmin) not working on Android 4.0+

我认为这个解决方案可以工作： 

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.os.AsyncTask;
import android.util.Log;
import android.widget.TextView;
//  
public class Connector extends AsyncTask<TextView, Void, String> {

    @Override
    protected String doInBackground(TextView... params) {
        // TODO Auto-generated method stub
        return GetSomething();
    }

    private final String getSomething() {   
         try{
                url=new URL("http://www.dynamiskdesign.se/ipromotionnew/json/148.json");
                HttpURLConnection httpURLConnection=(HttpURLConnection)url.openConnection();
                httpURLConnection.setRequestMethod("GET");
                httpURLConnection.setDoOutput(true);
                httpURLConnection.connect();
                InputStream input=httpURLConnection.getInputStream();

        } catch(Exception e) {
                Log.e("log_tag", "Error in http connection " + e.toString());
        }

        //convert response to string
        try{
                if (input != null) 
                {
                    writer = new StringWriter();
                    char[] buffer = new char[1024];
                    Reader reader = new BufferedReader(new InputStreamReader(input, "UTF-8"));
                    int n;
                    while ((n = reader.read(buffer)) != -1) {
                        writer.write(buffer, 0, n);
                    }
                    input.close();
                }

        } catch(Exception e) {
                Log.e("log_tag", "Error converting result "+e.toString());
        }
        //parse json data
        try {
                String jsontext = writer.toString();

        } catch(JSONException e) {
                Log.e("log_tag", "Error parsing data "+e.toString());
        }
        return returnString; 
    }    

    protected void onPostExecute(String page) {   
        //onPostExecute
    }   
}
于 2013-01-28T12:42:52.280 回答