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我有一个变量 start_time 和 end_time 以及另一个名为 confirm_time 的值。我需要做一个确认时间在 start_time 和 end_time 之间的匹配。我将如何发现。时间格式如下：

starting_time = "Jan 25 10:00:00"
ending_time   = "Jan 26 20:06:59"

Confirmed_time 也是相同的格式。

任何帮助将不胜感激

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6 回答 6

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您可以使用datetime.strptime将日期和时间解析为datetime对象并进行比较。请注意，重要的是每个时间的格式保持相同

>>> starting_time = "Jan 25 10:00:00"
>>> ending_time   = "Jan 26 20:06:59"
>>> confirmed_time = "Jan 25 11:11:11"
>>> starting_time_dt = datetime.strptime(starting_time,"%b %d %H:%M:%S")
>>> ending_time_dt   = datetime.strptime(ending_time,"%b %d %H:%M:%S")
>>> confirmed_time_dt   = datetime.strptime(confirmed_time,"%b %d %H:%M:%S")
>>> if starting_time_dt <= confirmed_time_dt <= ending_time_dt:
    print "Within ...."


Within ....
>>> confirmed_time = "Jan 24 11:11:11"
>>> confirmed_time_dt   = datetime.strptime(confirmed_time,"%b %d %H:%M:%S")
>>> if starting_time_dt <= confirmed_time_dt <= ending_time_dt:
    print "Within ...."


>>>
于 2013-01-28T08:14:37.953 回答
1

使用 dateutil 解析值并将它们转换为日期时间。然后检查您的确认时间是否在所需的时间间隔内。

于 2013-01-28T08:07:20.197 回答
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datetime 模块会有所帮助

In [41]: starting_time = "Jan 25 10:00:00"

In [42]: datetime.datetime.strptime(starting_time, "%b %d %H:%M:%S")
Out[42]: datetime.datetime(1900, 1, 25, 10, 0)

In [43]: s = datetime.datetime.strptime(starting_time, "%b %d %H:%M:%S")

In [44]: ending_time   = "Jan 26 20:06:59"

In [45]: e = datetime.datetime.strptime(ending_time, "%b %d %H:%M:%S")

In [46]: e
Out[46]: datetime.datetime(1900, 1, 26, 20, 6, 59)

In [47]: confirm_time   = "Jan 26 12:00:00"

In [48]: c = datetime.datetime.strptime(confirm_time, "%b %d %H:%M:%S")

In [49]: if s < c < e:
   ....:     print True
   ....:
True

检查这些可以在将字符串转换为日期时间对象时使用的格式

于 2013-01-28T08:15:16.557 回答
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我建议您安装并使用dateutlil 模块，因为它使解析日期更加容易。

from dateutil import parser

s_time = "Jan 25 10:00:00"
e_time = "Jan 26 20:06:59"
f_time = "Jan 25 12:10:00"

def example(conf, start, end):
    p = parser.parse
    return p(start) < p(conf) < p(end)

print example(f_time, s_time, e_time)
#output: True

parser.parse可以处理大多数甚至晦涩的格式：

In[21]: parser.parse("Sat Jan 26 00:31:17 UTC 2013")
Out[21]: datetime.datetime(2013, 1, 26, 0, 31, 17, tzinfo=tzutc())
于 2013-01-28T08:18:12.640 回答
0 
def isDateBetween(starting_time, ending_time, confirmed_time):
        pattern = '%b %d %H:%M:%S'

        startDate = datetime.datetime.strptime(starting_time, pattern)
        endDate = datetime.datetime.strptime(ending_time, pattern)
        confirmedDate = datetime.datetime.strptime(confirmed_time, pattern)

        return startDate <= confirmedDate <= endDate

print isDateBetween("Jan 25 10:00:00", "Jan 26 20:06:59", "Jan 27 12:20:00")
于 2013-01-28T08:19:43.783 回答
0

这有效：

import datetime as dt

starting_time = "Jan 25 10:00:00"
ending_time   = "Jan 26 20:06:59"
confirmed_time = "Jan 26 08:10:01"
fmt="%b %d %H:%M:%S"

print (dt.datetime.strptime(starting_time,fmt) < 
       dt.datetime.strptime(confirmed_time,fmt) < 
       dt.datetime.strptime(ending_time,fmt))

请注意，如果没有指定年份，则datetime默认为 1900。然而，缺少年份有点模糊。如果：

starting_time = "Dec 26 10:00:00"
ending_time   = "Jan 26 20:06:59"     # the following year or the same year? 
confirmed_time = "Jan 02 08:10:01"

编辑

您可以通过更改strptime 使用的输入格式来处理年份（如您的评论） ：

import datetime as dt

starting_time = "Dec 25 10:00:00 UTC 2012"
ending_time   = "Jan 26 20:06:59 UTC 2013"
confirmed_time = "Jan 02 08:10:01 UTC 2013"
fmt="%b %d %H:%M:%S UTC %Y"

print (dt.datetime.strptime(starting_time,fmt) < 
       dt.datetime.strptime(confirmed_time,fmt) < 
       dt.datetime.strptime(ending_time,fmt))
于 2013-01-28T08:21:21.543 回答