1

我有三个模型，Employee，Job，LeaveDay。如下所示：

class Employee
 field :name
 belongs_to :job
end
class Job
 field :job_title
 has_many :employees
 has_many :leave_days
end
class LeaveDay
 belongs_to :job    
 field :no_of_leave_days
end

我想建立一种关系，在这种关系中我想跟踪no_of_leave_days与其工作相关的员工。这怎么可能。提前致谢。

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2 回答 2

0

我认为您需要在 LeaveDay 中添加“belongs_to：employee”和在 Employee 中添加“has_many：leave_days”。因此，@emp.leave_days 将为您提供特定员工所有工作的所有假期。同样，@emp.job.leave_days 将返回 cuttent 员工当前工作的 leave_days。

于 2013-01-28T05:24:46.997 回答
0

我对 Mongoid 不是很熟悉。您可以在此处阅读更多关于 mongoid 关系的信息。

这是非常简单的例子。希望它会有所帮助。

这是模型定义：

class Employee
  include Mongoid::Document
  field :name
  belongs_to :job
end

class Job
  include Mongoid::Document
  field :job_title
  has_many :employees
  embeds_many :leave_days
end

class LeaveDay
  include Mongoid::Document
  embedded_in :job
  field :no_of_leave_days
end

以及使用示例：

pry(main)> j = Job.create(job_title: "Test Job")
=> #<Job _id: 510633e0784931179a000001, _type: nil, job_title: "Test Job">
pry(main)> LeaveDay.create(job: j, no_of_leave_days: 1)
=> #<LeaveDay _id: 5106348f784931179a000002, _type: nil, no_of_leave_days: 1>
pry(main)> LeaveDay.create(job: j, no_of_leave_days: 2)
=> #<LeaveDay _id: 51063687784931179a000003, _type: nil, no_of_leave_days: 2>
pry(main)> LeaveDay.create(job: j, no_of_leave_days: 3)
=> #<LeaveDay _id: 51063689784931179a000004, _type: nil, no_of_leave_days: 3>
pry(main)> Job.first.leave_days.map(&:no_of_leave_days)
=> [1, 2, 3]
pry(main)> Employee.create(name: 'Employee name', job: Job.first)
=> #<Employee _id: 510637cf784931179a000005, _type: nil, name: "Employee name", job_id:    "510633e0784931179a000001">
pry(main)> Employee.first.job.leave_days.map(&:no_of_leave_days)
=> [1, 2, 3]
于 2013-01-28T05:11:42.363 回答