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我正在尝试检查 sent1 或 sent2 的长度是否为零,如果他们有我想设置 sent_witn_not_null非零列表的列表。但是我写的 if-else 条件似乎很复杂。这样做的更简单方法是什么?

sent1 = ["this","is","foo","bar"]
sent2 = []

if len(sent1) or len(sent2) == 0:
    sent_with_not_null = sent2 if len(sent1) == 0 else sent1
    sent_with_not_null = sent1 if len(sent2) == 0 else sent2
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2 回答 2

1

利用 Python 的合并运算符

sent_with_not_null = sent2 and sent1
于 2013-01-28T03:44:25.290 回答
1

像这样的东西?

In [4]: if sent1 or sent2:
    sent_with_not_null=sent1 if sent1 else sent2
   ...:     

In [5]: sent_with_not_null
Out[5]: ['this', 'is', 'foo', 'bar']

或者:

In [11]: if any((sent1,sent2)): #in case both sent1 and sent2 are len==0

    sent_with_not_null =sent1 or sent2   #set the first True item to sent_with_not_null 
                                         #else the last one
   ....:     

In [12]: sent_with_not_null
Out[12]: ['this', 'is', 'foo', 'bar']
于 2013-01-28T03:50:12.037 回答