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我试图弄清楚如何使用 PHP 或 JavaScript 获取 Google 搜索结果。我知道以前有可能,但现在我找不到方法。

我正在尝试复制(某种程度上)
http://www.getupdated.se/sokmotoroptimering/seo-verktyg/kolla-ranking/的功能

但实际上我要解决的核心问题只是通过 PHP 或 JavaScript 获取搜索结果,其余的我可以弄清楚。

使用 file_get_contents() 或 cURL 获取结果似乎不起作用。

例子:

$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, 'http://www.google.se/#hl=sv&q=dogs');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
$result = curl_exec($ch);
curl_close($ch);
echo '<pre>';
var_dump($result);
echo '</pre>';

结果:

" string(219) "302 Moved 文档已移至此处。"

因此,通过一些谷歌搜索,我发现http://code.google.com/apis/customsearch/v1/overview.html但这似乎只适用于为一个或多个网站生成自定义搜索。似乎需要通过“自定义搜索引擎”cx 参数。

所以无论如何,有什么想法吗?

4

3 回答 3

8

我之前做过。通过发出 http 请求生成 html 内容https://www.google.co.in/search?hl=en&output=search&q=india,现在使用 htmldom php 库解析特定标签。您可以使用PHP SIMPLE HTML DOM解析结果页面的内容

演示:下面的代码将为您提供所有结果的标题:

<?php

include("simple_html_dom.php");

$html = file_get_html('http://www.google.co.in/search?hl=en&output=search&q=india');

$i = 0;
foreach($html->find('li[class=g]') as $element) {
    foreach($element->find('h3[class=r]') as $h3) 
    {
        $title[$i] = '<h1>'.$h3->plaintext.'</h1>' ;
    }
       $i++;
}
print_r($title);

?>
于 2013-01-27T20:50:13.863 回答
1

There is php a github package named google-url that does the job.

The api is very comfortable to use. See the example :

// this line creates a new crawler
$googleUrl=new \GoogleURL\GoogleUrl();
$googleUrl->setLang('en'); // say for which lang you want to search (it could have been "fr" instead)
$googleUrl->setNumberResults(10); // how many results you want to check
// launch the search for a specific keyword
$results = $googleUrl->search("google crawler");
// finaly you can loop on the results (an example is also available on the github page)

However you will have to think to use a delay between each query, or else google will consider you as a bot and ask you for a captcha that will lock the script.

于 2014-01-07T13:26:06.840 回答
0

奇怪的。因为如果我curl从命令中执行一个,就像我得到一个200 OK

curl -I 'http://www.google.se/#hl=sv&q=dogs'
HTTP/1.1 200 OK
Date: Sun, 27 Jan 2013 20:45:02 GMT
Expires: -1
Cache-Control: private, max-age=0
Content-Type: text/html; charset=ISO-8859-1
Set-Cookie: PREF=ID=b82cb66e9d996c48:FF=0:TM=1359319502:LM=1359319502:S=D-LW-_w8GlMfw-lX; expires=Tue, 27-Jan-2015 20:45:02 GMT; path=/; domain=.google.se
Set-Cookie: NID=67=XtW2l43TDBuOaOnhWkQ-AeRbpZOiA-UYEcs7BIgfGs41FkHlEegssgllBRmfhgQDwubG3JB0s5691OLHpNmLSNmJrKHKGZuwxCJYv1qnaBPtzitRECdLAIL0oQ0DSkrx; expires=Mon, 29-Jul-2013 20:45:02 GMT; path=/; domain=.google.se; HttpOnly
P3P: CP="This is not a P3P policy! See http://www.google.com/support/accounts/bin/answer.py?hl=en&answer=151657 for more info."
Server: gws
X-XSS-Protection: 1; mode=block
X-Frame-Options: SAMEORIGIN
Transfer-Encoding: chunked

另外,也许考虑urlencode为传递的 URL 设置一个,所以这一行:

curl_setopt($ch, CURLOPT_URL, 'http://www.google.se/#hl=sv&q=dogs');

对此的更改:

curl_setopt($ch, CURLOPT_URL, 'http://www.google.se/' . urlencode('#hl=sv&q=dogs'));
于 2013-01-27T20:49:08.573 回答