4

嗨，我正在尝试使用Spring-ws. 我对这个错误所做的谷歌搜索表明我使用的是 Soap 1.1 并且需要指定 Soap 1.2。我试过这样做。我在下面做对了吗？如果这不是问题，有人知道问题是什么吗？

这是堆栈跟踪的一部分： 

org.springframework.ws.client.WebServiceTransportException: Cannot process the message because the content type 'text/xml; charset=utf-8' was not the expected type 'application/soap+xml; charset=utf-8'. [415]
    at org.springframework.ws.client.core.WebServiceTemplate.handleError(WebServiceTemplate.java:663)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:587)
    at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:537)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:492)
    at org.springframework.ws.client.core.WebServiceTemplate.sendSourceAndReceiveToResult(WebServiceTemplate.java:436)
    at com.jda.fileserver.FujiAuthenticationTest.testLogin(FujiAuthenticationTest.java:53)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)

这是我的代码，感谢您的帮助：

public class AuthTest {
@Test
public void testLogin() throws Exception {
        StringBuffer loginXml = new StringBuffer();
        loginXml.append("<soapenv:Envelope xmlns:soapenv=\"http://www.w3.org/2003/05/soap-envelope\" xmlns:ns=\"http://abc.com/xyz/2010/08\">");
        loginXml.append("  <soapenv:Header>");
        loginXml.append("    <ns:loginOperationDetails>");
        loginXml.append("    </ns:loginOperationDetails>");
        loginXml.append("  </soapenv:Header>");
        loginXml.append("  <soapenv:Body>");
        loginXml.append("    <ns:LogIn>");
        loginXml.append("      <ns:logInInfo>");
        loginXml.append("        <ns:CustomerAccountId>customer1</ns:CustomerAccountId>");
        loginXml.append("        <ns:Username>jsmith</ns:Username>");
        loginXml.append("        <ns:Password>abc123</ns:Password>");
        loginXml.append("      </ns:logInInfo>");
        loginXml.append("    </ns:LogIn>");
        loginXml.append("  </soapenv:Body>");
        loginXml.append("</soapenv:Envelope>");

        WebServiceTemplate webServiceTemplate = new WebServiceTemplate();
        SaajSoapMessageFactory defaultMessageFactory = (SaajSoapMessageFactory) webServiceTemplate.getMessageFactory();
        defaultMessageFactory.setSoapVersion(SoapVersion.SOAP_12);
        webServiceTemplate.setMessageFactory(defaultMessageFactory); // probably not needed

        StreamSource source = new StreamSource(new StringReader(loginXml.toString()));
        StreamResult result = new StreamResult(System.out);
        String uri = "http://xyz.abcstage.com/xyz_1.0/membership.svc/ws";
        SoapActionCallback requestCallback = new SoapActionCallback("http://abc.com/xyz/2010/08/MembershipService/LogIn");
        try {
            webServiceTemplate.sendSourceAndReceiveToResult(uri, source, requestCallback, result);
        } 
        catch (SoapFaultException sfe) {
            throw new Exception("SoapFaultException", sfe);
        }
        catch (WebServiceTransportException wste) {
            throw new Exception("WebServiceTransportException", wste);
        }
    }
}
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4 回答 4

3

Ok, I fixed the above problem, which gets me to another problem. First here's how I fixed the above problem. Now I don't set the SOAP version on the SaajSoapMessageFactory, I set it on the wrapped MessageFactory. Now the Content-Type going out in my request is application/soap+xml. 

WebServiceTemplate webServiceTemplate = new WebServiceTemplate();
MessageFactory msgFactory = MessageFactory.newInstance(SOAPConstants.SOAP_1_2_PROTOCOL);
SaajSoapMessageFactory newSoapMessageFactory = new SaajSoapMessageFactory(msgFactory);
webServiceTemplate.setMessageFactory(newSoapMessageFactory);

Next problem, now I'm getting this:

org.springframework.ws.soap.client.SoapFaultClientException: Unexpected fault in the service.
    at org.springframework.ws.soap.client.core.SoapFaultMessageResolver.resolveFault(SoapFaultMessageResolver.java:37)
    at org.springframework.ws.client.core.WebServiceTemplate.handleFault(WebServiceTemplate.java:774)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:600)
    at org.springframework.ws.client.core.WebServiceTemplate.sendAndReceive(WebServiceTemplate.java:537)
    at org.springframework.ws.client.core.WebServiceTemplate.doSendAndReceive(WebServiceTemplate.java:492)
    at org.springframework.ws.client.core.WebServiceTemplate.sendSourceAndReceiveToResult(WebServiceTemplate.java:436)

and here's the info that was returned in the response: 

500 Internal Server Error
The SOAP action specified on the message, '', does not match the HTTP SOAP Action, 'http://abc.com/xyz/2010/08/MembershipService/LogIn'.

I'll try to solve this, but wanted to update anybody reading this so they can stop looking into the previous error. I need to figure out how to correctly set the soap action.

于 2013-01-28T19:12:34.937 回答
1

请使用以下代码在 Spring webservice 模板 marshallSendAndReceive 方法中将标头内容类型更改为 text/xml;charset=utf-8。

  WebServiceTemplate webServiceTemplate = new WebServiceTemplate();
webServiceTemplate.marshalSendAndReceive(url, request, new WebServiceMessageCallback() {

                public void doWithMessage(WebServiceMessage message) throws IOException, TransformerException {
                    SaajSoapMessage soapMessage = (SaajSoapMessage) message;
                    MimeHeaders headers = soapMessage.getSaajMessage().getMimeHeaders();
                    headers.addHeader(TransportConstants.HEADER_CONTENT_TYPE, "text/xml;charset=utf-8");
于 2018-12-07T09:56:05.073 回答
0

为了添加带有动作和标签的soapheader，下面的代码对我来说很好。

public void doWithMessage(WebServiceMessage message) throws IOException {
    SaajSoapMessage soapMessage = (SaajSoapMessage) message;

    SoapEnvelope soapEnvelope = soapMessage.getEnvelope();
    SoapHeader soapHeader = soapEnvelope.getHeader();

    //Initialize QName for Action and To
    QName action = new QName("{uri}", "Action", "{actionname}");
    QName to = new QName("{uri}", "To", "{actionname}");

    soapHeader.addNamespaceDeclaration("{actionname}", "{uri}");

    SoapHeaderElement soapHeaderElementAction = soapHeader.addHeaderElement(action);
    SoapHeaderElement soapHeaderElementTo = soapHeader.addHeaderElement(to);

    soapHeaderElementAction.setText("{text inside the tags}");

    soapHeaderElementTo.setText("{text inside the tags}");

    soapMessage.setSoapAction("{add soap action uri}");

    soapMessage.writeTo(out);

}
于 2019-06-28T20:53:11.897 回答
0

使用 setHeader 因为您可能想要替换现有标题的内容，或者如果它不存在则添加它。尽管 Httpheaders 应该是不区分大小写的，但使用 addHeader 就可以做到这一点。在调用 addHeader() 时通过源代码进行调试，即使它忽略大小写，您也会看到它在另一个标头之后插入新标头。所以，至少在Java中，最终会得到

内容类型：

内容类型：

            public void doWithMessage(WebServiceMessage message) throws IOException, TransformerException {
                SaajSoapMessage soapMessage = (SaajSoapMessage) message;
                MimeHeaders headers = soapMessage.getSaajMessage().getMimeHeaders();
                headers.setHeader(TransportConstants.HEADER_CONTENT_TYPE, "text/xml;charset=utf-8");
于 2021-05-26T22:19:03.337 回答