1

我希望带有 ImageAdapter 的 GridView 具有自定义按下的按钮。我已经有自定义按钮，但是 onClick 它会在按钮周围创建一个大的橙色 onClick 东西。我只想要 onClick 它显示我的自定义按下按钮。我应该如何轻松做到这一点？

图像适配器：

public class ImageAdapter extends BaseAdapter {
private Context context;
private final String[] buttonValues;

public ImageAdapter(Context context, String[] buttonValues) {
    this.context = context;
    this.buttonValues = buttonValues;
}

public View getView(int position, View convertView, ViewGroup parent) {

    LayoutInflater inflater = (LayoutInflater) context
        .getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    View gridView;

    if (convertView == null) {

        gridView = new View(context);

        // get layout from mobile.xml
        gridView = inflater.inflate(R.layout.mobile, null);


        // set image based on selected text
        ImageView imageView = (ImageView) gridView
                .findViewById(R.id.grid_item_image);

        String button = buttonValues[position];



        if (button.equals("homework")) {
            imageView.setImageResource(R.drawable.homework);
        } else if (button.equals("schedule")) {
            imageView.setImageResource(R.drawable.button_schedule);
        } else if (button.equals("planner")) {
            imageView.setImageResource(R.drawable.plannerbut);
        } else {
            imageView.setImageResource(R.drawable.settingsbut);
        }

    } else {
        gridView = (View) convertView;
    }

    return gridView;
}

@Override
public int getCount() {
    return buttonValues.length;
}

@Override
public Object getItem(int position) {
    return null;
}

@Override
public long getItemId(int position) {
    return 0;
}

}

还有我的活动（GridView 方法）：

private void setGridView() {
    gridView = (GridView) findViewById(R.id.gridView1);

    gridView.setAdapter(new ImageAdapter(this, MOBILE_OS));

    gridView.setOnItemClickListener(new OnItemClickListener() {
        public void onItemClick(AdapterView<?> parent, View v,
                int position, long id) {
            switch (position) {
            case 0:
                Toast.makeText(getApplicationContext(), "homework", Toast.LENGTH_SHORT).show();
                break;
            case 1:
                Toast.makeText(getApplicationContext(), "schedule", Toast.LENGTH_SHORT).show();
                break;

            case 2:
                Toast.makeText(getApplicationContext(), "planner",
                        Toast.LENGTH_SHORT).show();
                break;

            case 3:
                Toast.makeText(getApplicationContext(), "settings",
                        Toast.LENGTH_SHORT).show();
                break;
            }

        }
    });

}

提前致谢！

沃特

4

2 回答 2

1

您可以让您的按钮使用自定义可绘制对象，您可以在其中自己定义不同的状态。

<Button
    android:id="@+id/mybutton"
    android:background="@drawable/custom_button_selector" />

custom_button_selector.xml：

<?xml version="1.0" encoding="utf-8"?> 
<selector xmlns:android="http://schemas.android.com/apk/res/android"> 
    <item android:state_focused="true" android:state_pressed="true" 
        android:drawable="@drawable/bg_pressed" /> 
    <item android:state_focused="false" android:state_pressed="true" android:drawable="@drawable/bgalt" /> 
    <item android:drawable="@drawable/bg_normal" /> 
</selector>

然后在 bg_pressed/normal 中定义不同的按钮。

看看http://www.mkyong.com/android/android-imagebutton-selector-example/

于 2013-01-27T10:13:42.517 回答
0

我通过向我的 gridview 添加一个 ListSelector 并在 ImageAdapter 中添加一个选择器来修复它。

于 2013-01-29T06:28:04.183 回答