10

如何从此查询创建表值函数？

我需要计算HH:MM开始和结束工作时间之间的时间

当我在 SQL 中运行此查询时，它会起作用：

DECLARE @USERID int;
SET @USERID = 10

DECLARE @JOBStartDATE DATETIME;
SET @JOBStartDATE = (SELECT StartJOBHoursDATE FROM JOBs WHERE ID=@USERID) 


DECLARE @StartTime DATETIME;
DECLARE @JOBDateTime DATETIME;
DECLARE @JOBEvent nvarchar(50);
DECLARE @totalTime int;
SET @totalTime = 0;

SELECT  ROW_NUMBER() OVER(ORDER BY JOBID) AS ROWNUM, JOBDateTime,JOBEvent  INTO #TEMP FROM  JOBsActivityData where JOBID = @USERID and JOBDateTime >= @JOBStartDATE
DECLARE @MaxRownum INT
SET @MaxRownum = (SELECT MAX(RowNum) FROM #TEMP)
DECLARE @Iter INT
SET @Iter = (SELECT MIN(RowNum) FROM #TEMP)

WHILE @Iter <= @MaxRownum
BEGIN
SET @JOBDateTime =(SELECT JOBDateTime FROM #TEMP WHERE RowNum = @Iter)
SET @JOBEvent =(SELECT JOBEvent FROM #TEMP WHERE RowNum = @Iter)
IF(@JOBEvent = 'START')
BEGIN
SET @StartTime =(SELECT JOBDateTime FROM #TEMP WHERE RowNum = @Iter)
END
IF(@JOBEvent = 'END' AND @StartTime IS NOT NULL)
BEGIN
SET @totalTime = @totalTime + (SELECT DATEDIFF(minute,@StartTime,@JOBDateTime))
SET @StartTime = NULL;
END

    SET @Iter = @Iter + 1
END

DROP TABLE #TEMP

SELECT CAST((@totalTime / 60) AS VARCHAR(8)) + ':' + 
       CAST((@totalTime % 60) AS VARCHAR(2)) AS JOBHours

当我尝试创建时出现此错误

无法从函数内访问临时表。

4

2 回答 2

17

服务器不允许修改函数中的任何表。请改用表变量。

declare @temp table (RowNum int, JOBDateTime DateTime, JOBEvent int)

insert into @temp
  SELECT ROW_NUMBER() OVER(ORDER BY JOBID) AS ROWNUM, 
         JOBDateTime,
         JOBEvent  
    FROM JOBsActivityData 
   where JOBID = @USERID and JOBDateTime >= @JOBStartDATE
...

使用表变量时，不需要删除它们。

于 2013-01-27T07:42:49.370 回答
4

不要使用临时表，而是使用表变量，这应该可以解决您的问题。看到这个类似的问题Cannot access temporary tables from within a function

于 2013-01-27T07:41:39.210 回答