1

我有一个大文件，其中的“部分”由***. 我必须为每个部分创建一个散列和一个新文件，其中每个部分都以新格式写入（我可能为部分编写多个文件）。每个部分都需要独特的逻辑来转换为哈希（由“”或“\n”或“=”或“/某些模式/”分割）。
我正在寻找一种方法来识别部分并应用适当的逻辑将部分转换为哈希。我可以编写单独的逻辑片段，但它们是基于模式调用的单独方法或类吗？

由于文件很大，我试图逐行读取、操作和写入。我已经看到了在部分之间使用全局线的方法，但并不特别关心这种类型的解决方案。我对如何在部分之间抓取线条并在适当的时候逐行应用不同的逻辑有点困惑。

任何方向表示赞赏。谢谢！

这是一些输入文件：

  *** Summary ***

 Job Name = test   Date created: Mon Jan 14 15:48:33 2013


 *** Analysis Information 
 Steady State is ON
 Turbulent Incompressible Flow is ON 
 Static Temperature Equation is ON
 Mixed Convection is ON

 *** Field Variable Results Summary For Iteration 300


  Var      Mean          at      Max          at      Min
 Vx Vel  +5.71519e+002 1320103 +3.02718e+004 1319857 -2.66582e+004 mm/s
 Vy Vel  +3.40035e+002 158922 +2.79257e+004 1319731 -1.42855e+004 mm/s
 Vz Vel  -7.17959e+002 1318038 +1.62986e+004 1319053 -2.21582e+004 mm/s
 Press  -2.05980e+001  50858 +5.19412e+003  50905 -1.44865e+003 N/m^2
 Temp  +4.60000e+001  10965 +4.60000e+001 315867 +4.60000e+001 C
 TurbK  +1.19616e+006 1319490 +1.44421e+008  10966 +1.81700e-008 mm^2/s^2
 TurbD  +1.71412e+009 1319490 +2.88554e+011 233065 +5.37798e-004 mm^2/s^3
 Scal1  +0.00000e+000  10965 +0.00000e+000 315867 +0.00000e+000  
 PTotl  -5.91285e+000  50858 +5.19412e+003  50905 -1.44865e+003 N/m^2
 EVisc  +2.52037e-004 1320370 +1.14488e-002   2229 +0.00000e+000 g/mm-s
 ECond  +1.05355e-002 1352833 +5.88890e-002   2229 +0.00000e+000 W/mm-K
 Dens  +2.34793e-004  58024 +3.43080e-003 315867 +1.20473e-006 g/mm^3
 Visc  +1.62605e-005  10965 +1.81700e-005   2229 +0.00000e+000 g/mm-s
 Cond  +2.50840e-002   2229 +2.04000e-001 315867 +2.56300e-005 W/mm-K
 SpecH  +1.01202e+000  38432 +1.81000e+000  10249 +1.00500e-003 J/g-K
 Emiss  +8.94911e-001  10965 +1.00000e+000   2229 +0.00000e+000  
 Transmiss  +0.00000e+000      0 +0.00000e+000      0 +0.00000e+000  
 WRough  +0.00000e+000  10965 +0.00000e+000 315867 +0.00000e+000 mm
 SeeBeck  +0.00000e+000      0 +0.00000e+000      0 +0.00000e+000 V/K
 GenT  +1.11977e+003 223286 +1.18027e+005 584515 +3.19558e-013 1/s


*** Openings ***


         *** Outlet 1 ***

  Surface ID = 2329

  Node near Minimum X,Y,Z of opening = 11761

  Minimum X,Y,Z of opening = 369.964000, 11.275438, -98.433898

     Mass Flow Out            = -1.55703 g/s
  Volume Flow Out            = -1.29242e+006 mm^3/s
     Reynolds Number         = 1303.45
     Outlet Bulk Pressure    = -0 N/m^2
     Outlet Bulk Temperature = 46 C
     Outlet Mach Number      = 0.00734951


         *** Outlet 2 ***

  Surface ID = 2332

  Node near Minimum X,Y,Z of opening = 11125

  Minimum X,Y,Z of opening = 369.964000, 73.727289, -114.615876

     Mass Flow Out            = -20.4612 g/s
  Volume Flow Out            = -1.6984e+007 mm^3/s
     Reynolds Number         = 11182.5
     Outlet Bulk Pressure    = -0 N/m^2
     Outlet Bulk Temperature = 46 C
     Outlet Mach Number      = 0.0079087


         *** Outlet 3 ***

  Surface ID = 2335

  Node near Minimum X,Y,Z of opening = 10924

  Minimum X,Y,Z of opening = 369.964000, 164.751344, 40.640056

     Mass Flow Out            = -32.8714 g/s
  Volume Flow Out            = -2.72852e+007 mm^3/s
     Reynolds Number         = 17965
     Outlet Bulk Pressure    = -0 N/m^2
     Outlet Bulk Temperature = 46 C
     Outlet Mach Number      = 0.00750077

*** Fluid Energy Balance Information:
  MdotIn x Cp x (TOut - TIn) =       663.69 Watts
 (Numerical) Energy Out  -  Energy In =      0.36447 Watts
     Heat Transfer from Wall To Fluid =       761.35 Watts
Heat Transfer Due to Sources In Fluid =            0 Watts

*** Solid Energy Balance Information:
 Heat Transfer from Exterior To Solid =            0 Watts
Heat Transfer Due to Sources In Solid =          761 Watts
    Heat Transfer From Fluid To Solid =      -761.31 Watts

*** Sum of Fluid Forces on Walls ***
   ShearX, PressX =        68651         78199   microNewtons
   ShearY, PressY =        39030   6.9349e+006   microNewtons
   ShearZ, PressZ =       -19749  -4.1017e+006   microNewtons

*** Data for internal fans 

Fan Part Id = 16 Fan Name = fname1
Operating Pressure Rise = 0.46945 Inches of Water
Operating FlowRate = 36.0109 CFM

Fan Part Id = 94 Fan Name = fname2
Operating Pressure Rise = 0.309645 Inches of Water
Operating FlowRate = 2.33407 CFM

Fan Part Id = 95 Fan Name = fname3
Operating Pressure Rise = 0.267133 Inches of Water
Operating FlowRate = 8.78264 CFM


*** Analysis Statistics: 

 Input:              461 seconds 
 Analysis:         12686 seconds 
 Output:             179 seconds 
 Total:            13326 seconds

到目前为止，这是我所拥有的：

sum_file = File.new('sum_file.sum', 'r')
sum_file_hashed = File.new('sum_file_hashed', 'w')

inSection = false #flag when in or out of a section?

    while (line = sum_file.gets ) #while reading lines
        case line
        when /\*{3}/ #Found Sections by ***
            inSection = true #in a section
            l = line.gsub('*', '').strip
            sum_file_hashed.puts('Found a section: ' + l ) #write section name
        end

        ### I'm not sure how to introduce specific logic when in a certain type of section ###

    end

sum_file.close
sum_file_hashed.close

我现在正在尝试类似的东西：

while /found section/
  if /match pattern a/
    call parsera
  if /match pattern b/
    call parserb
end

parsera 
while =! /a section/
do stuff
return?
4

2 回答 2

3

Ruby 的 Enumerable containsslice_before非常适合这种任务，它根据某些标记将文件分解为块。

require 'pp'

blocks = DATA.readlines.map(&:strip).reject{ |l| l == '' }.slice_before(/\A\*{3}/)
pp blocks.to_a

__END__
  *** Summary ***

 Job Name = test   Date created: Mon Jan 14 15:48:33 2013


 *** Analysis Information 
 Steady State is ON
 Turbulent Incompressible Flow is ON 
 Static Temperature Equation is ON
 Mixed Convection is ON

 *** Field Variable Results Summary For Iteration 300


  Var      Mean          at      Max          at      Min
 Vx Vel  +5.71519e+002 1320103 +3.02718e+004 1319857 -2.66582e+004 mm/s
 Vy Vel  +3.40035e+002 158922 +2.79257e+004 1319731 -1.42855e+004 mm/s
 Vz Vel  -7.17959e+002 1318038 +1.62986e+004 1319053 -2.21582e+004 mm/s
 Press  -2.05980e+001  50858 +5.19412e+003  50905 -1.44865e+003 N/m^2
 Temp  +4.60000e+001  10965 +4.60000e+001 315867 +4.60000e+001 C
 TurbK  +1.19616e+006 1319490 +1.44421e+008  10966 +1.81700e-008 mm^2/s^2
 TurbD  +1.71412e+009 1319490 +2.88554e+011 233065 +5.37798e-004 mm^2/s^3
 Scal1  +0.00000e+000  10965 +0.00000e+000 315867 +0.00000e+000  
 PTotl  -5.91285e+000  50858 +5.19412e+003  50905 -1.44865e+003 N/m^2
 EVisc  +2.52037e-004 1320370 +1.14488e-002   2229 +0.00000e+000 g/mm-s
 ECond  +1.05355e-002 1352833 +5.88890e-002   2229 +0.00000e+000 W/mm-K
 Dens  +2.34793e-004  58024 +3.43080e-003 315867 +1.20473e-006 g/mm^3
 Visc  +1.62605e-005  10965 +1.81700e-005   2229 +0.00000e+000 g/mm-s
 Cond  +2.50840e-002   2229 +2.04000e-001 315867 +2.56300e-005 W/mm-K
 SpecH  +1.01202e+000  38432 +1.81000e+000  10249 +1.00500e-003 J/g-K
 Emiss  +8.94911e-001  10965 +1.00000e+000   2229 +0.00000e+000  
 Transmiss  +0.00000e+000      0 +0.00000e+000      0 +0.00000e+000  
 WRough  +0.00000e+000  10965 +0.00000e+000 315867 +0.00000e+000 mm
 SeeBeck  +0.00000e+000      0 +0.00000e+000      0 +0.00000e+000 V/K
 GenT  +1.11977e+003 223286 +1.18027e+005 584515 +3.19558e-013 1/s

我缩短了数据，因为样本太多了。

运行代码输出：

[[“*** 概括 ***”，
  "职位名称 = 测试创建日期：2013 年 1 月 14 日星期一 15:48:33"],
 ["***分析信息",
  “稳态开启”，
  “湍流不可压缩流开启”，
  “静态温度方程为 ON”，
  "混合对流开启"],
 ["*** 迭代 300 的字段变量结果摘要",
  “最小值处最大值处的方差均值”，
  “Vx 速度 +5.71519e+002 1320103 +3.02718e+004 1319857 -2.66582e+004 毫米/秒”，
  "Vy Vel +3.40035e+002 158922 +2.79257e+004 1319731 -1.42855e+004 mm/s",
  “Vz 速度 -7.17959e+002 1318038 +1.62986e+004 1319053 -2.21582e+004 毫米/秒”，
  "按-2.05980e+001 50858 +5.19412e+003 50905 -1.44865e+003 N/m^2",
  "温度 +4.60000e+001 10965 +4.60000e+001 315867 +4.60000e+001 C",
  "TurbK +1.19616e+006 1319490 +1.44421e+008 10966 +1.81700e-008 mm^2/s^2",
  "涡轮 D +1.71412e+009 1319490 +2.88554e+011 233065 +5.37798e-004 mm^2/s^3",
  "标度1 +0.00000e+000 10965 +0.00000e+000 315867 +0.00000e+000",
  "PTotl -5.91285e+000 50858 +5.19412e+003 50905 -1.44865e+003 N/m^2",
  "EVisc +2.5203​​7e-004 1320370 +1.14488e-002 2229 +0.00000e+000 g/mm-s",
  "ECond +1.05355e-002 1352833 +5.88890e-002 2229 +0.00000e+000 W/mm-K",
  "密度 +2.34793e-004 58024 +3.43080e-003 315867 +1.20473e-006 g/mm^3",
  "粘度 +1.62605e-005 10965 +1.81700e-005 2229 +0.00000e+000 g/mm-s",
  "条件 +2.50840e-002 2229 +2.04000e-001 315867 +2.56300e-005 W/mm-K",
  “规格 H +1.01202e+000 38432 +1.81000e+000 10249 +1.00500e-003 J/gK”，
  "发射 +8.94911e-001 10965 +1.00000e+000 2229 +0.00000e+000",
  "传输 +0.00000e+000 0 +0.00000e+000 0 +0.00000e+000",
  "WRough +0.00000e+000 10965 +0.00000e+000 315867 +0.00000e+000 mm",
  "SeeBeck +0.00000e+000 0 +0.00000e+000 0 +0.00000e+000 V/K",
  "GenT +1.11977e+003 223286 +1.18027e+005 584515 +3.19558e-013 1/s"]]

该文件已转换为数组数组。前导和尾随空格，以及换行符和回车符被剥离，空白行被删除。

进一步处理文件是使用外部数组上的循环和查看每个子数组的第一行以确定如何处理该块的测试来完成的。这样的事情将是一个起点：

hash = {}
blocks.each do |block|
  case block.shift
  when /Summary/
    # process the summary information

  when /Analysis Information/
    # process the analysis information
    hash[:analysis_information] = Hash[block.map{ |r| r.split(/ +is +/) }]

  when /Field Variable Results/
    # process the field variable results

  end
end

这个想法是，当代码完成时，hash将包含散列散列或数组散列中的解析数据，准备好写出来。我建议使用 YAML，因为它可以缩短将数据序列化为文件的工作。

我不会添加更多内容，因为这个问题听起来很像家庭作业，而且解析这些行并不难。将文件分成块是一项更大的任务，这部分已经为您完成了。

于 2013-01-26T05:19:04.550 回答
1

您可以将部分中的所有行添加到数组中。如果下一部分开始或您位于文件末尾，则使用此数组作为参数调用特定于部分的方法。这样您就不必在检测部分时处理部分逻辑。

编辑： 未经测试，但这应该给出一个想法：

def parse_section_name(name)
  name.gsub!(/\*/, '') # remove *'s
  return name.strip # remove whitespace from both sides
end

def call_section_logic(name, lines)
  case name
  when ...
  ...
  else # unknown name
  end
end

section_lines = []
lines = file.readlines + ['***'] # add last section, too
lines.each do |line|
  if line =~ /^\s*\*{3}/ # detect section
    call_section_logic(section_name, section_lines)
    section_name = parse_section_name(line)
    section_lines.clear
  else
    section_lines << line # add line to array
  end
end
于 2013-01-26T00:10:02.393 回答