我有以下表格:
Material
material_ID | material_Name
A | Sugar
B | Flour
C | Egg Yolk
D | Water
E | Tea Powder
Product
product_ID | product_Name | material_ID
1 | Cake | A
1 | Cake | B
1 | Cake | C
2 | Tea | D
2 | Tea | E
2 | Tea | A
ScaleData
record_ID | product_ID | material_ID | Weight
1001 | 1 | A | 30
1002 | 1 | B | 11
1003 | 1 | C | 25
1004 | 1 | A | 31
1005 | 1 | B | 25
1006 | 2 | D | 15
1007 | 2 | E | 20
1008 | 2 | E | 21
如您所见:产品 1 是蛋糕,它需要材料:A、B 和 C 才能形成完整的产品。产品 2 是茶,它需要材料:D、E 和 A 才能形成完整的产品。
From the weighing table (ScaleData) we can see that there is 1 cake and 0 tea.
record_ID: 1001, 1002, 1003 creates one complete cake.
record_ID: 1004, 1005 are remaining incomplete cake ingredients.
record_ID: 1006, 1007, 1008 are remaining incomplete tea ingredients.
Question:
A. How can i create the following result table based on data from above tables:
Result
product_ID | product_Name | Qty
1 | Cake | 1
2 | Tea | 0
B. How can i display the remaining ingredients like below?
Remaining
record_ID | product_ID | material_ID | Weight
1004 | 1 | A | 31
1005 | 1 | B | 25
1006 | 2 | D | 15
1007 | 2 | E | 20
1008 | 2 | E | 21
编辑:我目前能够通过混合使用 .NET 代码 + SQL 查询来解决这个问题。我正在寻找的是纯 SQL 查询解决方案。我目前的方法如下:
1. Execute: "SELECT DISTINCT product_ID FROM Product" to get a list of Product_ID.
2. Iterate through each product_ID and retrieve list of material from each product.
Something like: "SELECT material_ID FROM Product WHERE product_ID=1"
3. Scan ScaleData table for each material and get the total row counts
Something like:
TotalA = "SELECT COUNT(*) FROM ScaleData WHERE product_ID=1 AND material_ID='A'
TotalB = "SELECT COUNT(*) FROM ScaleData WHERE product_ID=1 AND material_ID='B'
TotalC = "SELECT COUNT(*) FROM ScaleData WHERE product_ID=1 AND material_ID='C'
4. Compare variables: TotalA, TotalB, TotalC and get the lowest value.
Lets say TotalA = 2 ; TotalB = 2 ; TotalC = 1
LowestCount = TotalC = 1
5. Then we can tell total Qty for product 1 is 1 ( based on lowest count ).
Remaining for Material A = 2 - 1 = 1
Remaining for Material B = 2 - 1 = 1
这是我目前的解决方案,我知道它不是很有效。我更喜欢纯 SQL 解决方案,我希望一些 SQL 大师愿意帮助我..