我正在尝试放入 sqldatabase 2 列。当我插入评论时一切都很好，但是当我尝试阅读 listView 时出现错误。column '_id' does not exist
有logcat：
01-25 12:30:55.787: E/AndroidRuntime(4256): FATAL EXCEPTION: main
01-25 12:30:55.787: E/AndroidRuntime(4256): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.spacebrowser/com.example.spacebrowser.books}: java.lang.IllegalArgumentException: column '_id' does not exist
有Sqliteadapter
public class SQLiteAbdapter {
public static final String MYDATABASE_NAME = "MY_DATABASES";
public static final String MYDATABASE_TABLE = "MY_TABLE";
public static final int MYDATABASE_VERSION = 1;
public static final String KEY_ID = "_id";
public static final String KEY_CONTENT1 = "Content1";
public static final String KEY_CONTENT2 = "Content2";
private static final String SCRIPT_CREATE_DATABASE =
"create table " + MYDATABASE_TABLE + " ("
+ KEY_ID + " integer primary key autoincrement, "
+ KEY_CONTENT1 + " text not null, "
+ KEY_CONTENT2 + " text not null);";
private SQLiteHelper sqLiteHelper;
private SQLiteDatabase sqLiteDatabase;
private Context context;
public SQLiteAbdapter(Context c){
context = c;
}
public SQLiteAbdapter openToRead() throws android.database.SQLException {
sqLiteHelper = new SQLiteHelper(context, MYDATABASE_NAME, null, MYDATABASE_VERSION);
sqLiteDatabase = sqLiteHelper.getReadableDatabase();
return this;
}
public SQLiteAbdapter openToWrite() throws android.database.SQLException {
sqLiteHelper = new SQLiteHelper(context, MYDATABASE_NAME, null, MYDATABASE_VERSION);
sqLiteDatabase = sqLiteHelper.getWritableDatabase();
return this;
}
public void close(){
sqLiteHelper.close();
}
public long insert(String content1, String content2){
ContentValues contentValues = new ContentValues();
contentValues.put(KEY_CONTENT1, content1);
contentValues.put(KEY_CONTENT2, content2);
return sqLiteDatabase.insert(MYDATABASE_TABLE, null, contentValues);
}
public int deleteAll(){
return sqLiteDatabase.delete(MYDATABASE_TABLE, null, null);
}
public Cursor queueAll(){
String[] columns = new String[]{KEY_ID, KEY_CONTENT1, KEY_CONTENT2};
Cursor cursor = sqLiteDatabase.query(MYDATABASE_TABLE, columns,
null, null, null, null, null, null);
return cursor;
}
public class SQLiteHelper extends SQLiteOpenHelper {
public SQLiteHelper(Context context, String name,
CursorFactory factory, int version) {
super(context, name, factory, version);
}
@Override
public void onCreate(SQLiteDatabase db) {
// TODO Auto-generated method stub
db.execSQL(SCRIPT_CREATE_DATABASE);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// TODO Auto-generated method stub
if (oldVersion >= newVersion)
return;
db.execSQL("DROP TABLE IF EXISTS " + MYDATABASE_TABLE);
onCreate(db);
}
}
}
还有books.java simplecursoradapter：
ListView listContent;
private SQLiteAbdapter mySQLiteAdapter;
SimpleCursorAdapter cursorAdapter;
Cursor cursor;
@SuppressWarnings("deprecation")
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.books);
listContent = (ListView)findViewById(R.id.list);
mySQLiteAdapter = new SQLiteAbdapter(this);
mySQLiteAdapter.openToRead();
cursor = mySQLiteAdapter.queueAll();
String[] from = new String[]{SQLiteAdapter.KEY_ID, SQLiteAbdapter.KEY_CONTENT1, SQLiteAbdapter.KEY_CONTENT2};
int[] to = new int[]{R.id.id, R.id.title, R.id.urlss};
cursorAdapter =
new SimpleCursorAdapter(this, R.layout.bookmark, cursor, from, to);
listContent.setAdapter(cursorAdapter);
我做的这么糟糕，以至于我有这个错误？
column '_id' does not exist