27

假设我有一个包含电影演员姓名和他们去过的电影的非标准化表格。例如。

CREATE TABLE movies_actors (
  movies_actors_id INT,
  movie VARCHAR(255),
  actor VARCHAR(255),
  PRIMARY KEY (movies_actors_id)
);

我会SELECT actor, COUNT(1) FROM movies_actors GROUP BY actor查明该演员参演了多少部电影。但我也想查明该演员参演的电影的百分比。

我想我可以这样做：

SELECT
  actor,
  COUNT(1) AS total,
  COUNT(1) / (SELECT COUNT(1) FROM movies_actors) * 100 AS avg
FROM movies_actors
GROUP BY actor;

但这似乎...... idk...... 恶心。

有任何想法吗？

4

5 回答 5

36

对于大型集合，JOIN 可能比子查询执行得更好。

SELECT ma.actor
     , COUNT(1) AS total
     , COUNT(1) / t.cnt * 100 AS `percentage`
  FROM movies_actors ma
 CROSS
  JOIN (SELECT COUNT(1) AS cnt FROM movies_actors) t
 GROUP
    BY ma.actor
     , t.cnt

对于大型集合，并且当返回很大比例的行时，JOIN 操作通常可以胜过子查询。在你的情况下，它不是一个相关的子查询，所以 MySQL 不应该多次执行，所以它可能没有任何区别。

请注意，对于 ... 的非粉丝，COUNT(1)我们可以将任何和所有出现的 替换为COUNT(1)orCOUNT(*)以IFNULL(SUM(1),0)达到等效的结果。

于 2013-01-25T05:45:51.460 回答
2

每当您想从同一个表中获取操作数据时，请执行自交叉连接。

SELECT
m.actor,
COUNT(m.actor) AS total,
(COUNT(m.actor) / t.total_movies) * 100 AS avg
FROM movies_actors m
cross (select count(*) as total_movies from movies_actors) t
GROUP BY m.actor;
于 2013-01-25T05:57:18.317 回答
2

不使用连接和多个查询：-

select actor,counter,  100 * counter / @total as percentage
from(
select actor, 
        case when actor is null
            then @total := count(*)
            else count(*)
        end as counter
    from movies_actors 
    group by actor
    with rollup
) mytable
于 2019-07-18T12:29:39.173 回答
0

我不确定它是否“更好”，但你可以做一个 SUM 并在其他地方做数学：

SELECT actor,
    COUNT(1) AS total,
    SUM(oneMoviePercentPts) AS percentage
FROM movies_actors
CROSS JOIN 
(
    SELECT 100 / CAST(COUNT(1) AS DECIMAL(15,4)) AS oneMoviePercentPts 
    FROM movies_actors
) t
GROUP BY actor

我希望 MySQL 优化器足够聪明，不会多次执行您的子查询，但连接语法使这一点变得明确。

于 2013-01-25T05:47:57.357 回答
0

这对我有用：

SELECT tmpTotal.yearmonth, tmpTotal.rec_count, 
      (tmpTotal.rec_count / @myCumul) * 100 AS myPercentage
FROM
(
  SELECT tmpResult.*, @myCumul := @myCumul + tmpResult.rec_count AS myNewCumul
  FROM
  (
    SELECT date_format(d.created_at, '%Y/%m') as yearmonth, count(*) rec_count
    FROM cf4a_webapp.factTable d 
      join cf4a_webapp.dimTable c on (d.client_id = c.id)
    WHERE c.id = 25 
      AND d.created_at >= '2019-01-01 00:00:01' 
      AND d.created_at < '2020-01-01 00:00:01'
    GROUP BY yearmonth
  ) tmpResult
  JOIN (SELECT @myCumul := 0) tmpCumul
) tmpTotal;
于 2020-03-06T17:26:11.590 回答