python - 试图得到一个很好的格式输出，简单的 Python

Question

board = []
for integer in range(1,6):
    board.append("O")
print(str(board)*5)

那是我的代码。我的问题是输出不是 5x5 网格。我错过了另一个 for 循环吗？（我知道我也可以使用列表推导）。

谢谢你。

Answer 1

如果你想要一个5x5网格，你可以join得到结果......

'\n'.join([' '.join(board)]*5)

例子：

>>> board = ['0']*5
>>> print '\n'.join([' '.join(board)]*5)
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0

要获得您正在寻找的输出，您可以这样做

>>> board = [['0'] for _ in range(5)]
>>> board
[['0'], ['0'], ['0'], ['0'], ['0']]
>>> print '\n'.join(str(board) for _ in range(5))
[['0'], ['0'], ['0'], ['0'], ['0']]
[['0'], ['0'], ['0'], ['0'], ['0']]
[['0'], ['0'], ['0'], ['0'], ['0']]
[['0'], ['0'], ['0'], ['0'], ['0']]
[['0'], ['0'], ['0'], ['0'], ['0']]

Answer 2

In [22]: board = [['O'] * 5 for _ in range(5)]

In [23]: print('\n'.join(''.join(row) for row in board))
OOOOO
OOOOO
OOOOO
OOOOO
OOOOO

Answer 3

您缺少换行符：

 print(('0'*6+'\n')*5)

Answer 4

您不应使用JOIN将数据打印到列中，因为当您的数据中包含可变数量的字符时，它们不会对齐。请改用字符串格式。

boardLst = [[0 for i in range(1,6)]]*5
for board in boardLst:
    print "  %4d"*len(board) % tuple(board), "\n"

 0     0     0     0     0 

 0     0     0     0     0 

 0     0     0     0     0 

 0     0     0     0     0 

 0     0     0     0     0 

字符串格式化程序中的数字 4 表示字符之间的最小空格量。

现在，如果您创建一个具有可变长度字符的列表，如下所示，您可以打印漂亮的列：

import random
boardLst = [[random.randint(1,125) for i in range(1,5)] for _ in range(8)]
for board in boardLst:
    print " %5d "*len(board) % tuple(board), "\n"


  107     93     10     73  

   65     68     81     61  

   49     75     58     18  

   48     78     18     37  

   82      4     78    101  

   20      9     68     86  

   24     77     20     52  

   20    120     93     21