如何从 Hibernate 中删除对象?
Session session = HibernateSession.getSessionFactory().openSession();
org.hibernate.Transaction tx = session.beginTransaction();
int q = session.createQuery("from Modele where (model='"+u.getModel() +"' and markaid='"+u.getMarki().getId()+"'").executeUpdate();
// session.delete(u);
session.getTransaction().commit();
信息:不支持!使用 AST 翻译器...
改为使用时session.delete(u)
,我得到了这个
INFO:在删除处理中处理瞬态实体
CREATE TABLE modele
(
id serial NOT NULL,
markaid integer NOT NULL,
cena numeric(100,2),
model character varying(32),
CONSTRAINT k_glwny PRIMARY KEY (id),
CONSTRAINT obcy FOREIGN KEY (markaid)
REFERENCES marki (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE CASCADE
)
<hibernate-mapping>
<class name="bazaMap.Modele" table="modele" schema="public">
<id name="id" type="int">
<column name="id" />
<generator class="identity" />
</id>
<many-to-one name="marki" class="bazaMap.Marki" fetch="select">
<column name="markaid" not-null="true" />
</many-to-one>
<property name="cena" type="java.lang.Double">
<column name="cena" scale="0" />
</property>
<property name="model" type="string">
<column name="model" length="32" />
</property>
<set name="wypozyczenias" inverse="true">
<key>
<column name="modelid" not-null="true" />
</key>
<one-to-many class="bazaMap.Wypozyczenia" />
</set>
</class>
</hibernate-mapping>
这也行不通
session.createQuery("from Modele where model = :mmodel and markaid = :mmarkaid").setParameter("mmodel", u.getModel()).setParameter("mmarkaid", u.getMarki().getId()).executeUpdate();