sql - sql函数中的协助

Question

我之前已经在下面发布了编写的代码，并得到了正确的代码并消除了错误，但我的标准不令人满意，下面是作为参数传递的原始数据

 2007:10113:/I/69071/MLI/Eldridge

作为回报，输出应该是“69071”，为此我给出了以下函数，但我没有得到输出，而且我还保留了一些其他条件来满足其他要求，请帮助我。

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON  --2007:10113:/I/69071/MLI/Eldridge
go
ALTER FUNCTION [dbo].[Empnum] (@RAWDATA NVARCHAR(300))
RETURNS VARCHAR(30)
 AS
BEGIN
DECLARE @TEMP1 NVARCHAR(300), @EMPNUM NVARCHAR(10), @TEMP2 NVARCHAR(300), @TEMP3 NVARCHAR(300)
SET @TEMP3 = 'Disabled'
SET @EMPNUM=''
SET @TEMP2 = @RAWDATA
IF( CHARINDEX(@TEMP3,@RAWDATA,1) = 0) 
BEGIN
--   SET @EMPNUM='11'
 IF ISNUMERIC(SUBSTRING(@RAWDATA,1,1)) = 1
      BEGIN     
 --             
       IF((LEN(@RAWDATA) - LEN(REPLACE(@TEMP2,'/','')))>1)
             BEGIN
             SET @RAWDATA=SUBSTRING(@RAWDATA,CHARINDEX('/',@RAWDATA)+1,LEN(@RAWDATA))    
              SET @RAWDATA=SUBSTRING(@RAWDATA,CHARINDEX('/',@RAWDATA)+1,LEN(@RAWDATA))    
               SET @RAWDATA=SUBSTRING(@RAWDATA,1,CHARINDEX('/',@RAWDATA)-1)
  IF( CHARINDEX('*C',@RAWDATA) = 0 OR
     CHARINDEX('CV',@RAWDATA) = 0 OR
     CHARINDEX('AV',@RAWDATA) = 0 OR
     CHARINDEX('LV',@RAWDATA) = 0 ) 
      BEGIN 
         SET @EMPNUM = ''
         RETURN @EMPNUM
     END
  ELSE 
     BEGIN
         IF ISNUMERIC(SUBSTRING(@RAWDATA,1,1)) = 1
             BEGIN
                 SET @EMPNUM = @RAWDATA
                 RETURN @EMPNUM
          END 
 ELSE
     IF((SUBSTRING(@RAWDATA,1,1)='C') AND ISNUMERIC(SUBSTRING(@RAWDATA,2,1)) = 1)
         BEGIN
             SET @EMPNUM = SUBSTRING(@RAWDATA,2,LEN(@RAWDATA))
             RETURN @EMPNUM
         END
END
 END
END
END
  RETURN @EMPNUM
 END

Answer 1

我在我的代码中发现了错误，并更改了“=”o“<>”

IF( CHARINDEX('*C',@RAWDATA) <> 0 OR
 CHARINDEX('CV',@RAWDATA) <> 0 OR
 CHARINDEX('AV',@RAWDATA) <> 0 OR
 CHARINDEX('LV',@RAWDATA) <> 0 ) 
 BEGIN 
     SET @EMPNUM = ''
     RETURN @EMPNUM
 END