我想用控制框在画布上绘制一个圆柱体来调整圆柱体的大小。
问问题
7343 次
4 回答
3
这是我为回答我自己的问题而创建的一些 javascript 代码:
function drawCylinder ( x, y, w, h ) {
context.beginPath(); //to draw the top circle
for (var i = 0 * Math.PI; i < 2 * Math.PI; i += 0.001) {
xPos = (this.x + this.w / 2) - (this.w / 2 * Math.sin(i)) *
Math.sin(0 * Math.PI) + (this.w / 2 * Math.cos(i)) *
Math.cos(0 * Math.PI);
yPos = (this.y + this.h / 8) + (this.h / 8 * Math.cos(i)) *
Math.sin(0 * Math.PI) + (this.h / 8 *
Math.sin(i)) * Math.cos(0 * Math.PI);
if (i == 0) {
context.moveTo(xPos, yPos);
}
else
{
context.lineTo(xPos, yPos);
}
}
context.moveTo(this.x, this.y + this.h / 8);
context.lineTo(this.x, this.y + this.h - this.h / 8);
for (var i = 0 * Math.PI; i < Math.PI; i += 0.001) {
xPos = (this.x + this.w / 2) - (this.w / 2 * Math.sin(i)) * Math.sin(0 * Math.PI) + (this.w / 2 * Math.cos(i)) * Math.cos(0 * Math.PI);
yPos = (this.y + this.h - this.h / 8) + (this.h / 8 * Math.cos(i)) * Math.sin(0 * Math.PI) + (this.h / 8 * Math.sin(i)) * Math.cos(0 * Math.PI);
if (i == 0) {
context.moveTo(xPos, yPos);
}
else
{
context.lineTo(xPos, yPos);
}
}
context.moveTo(this.x + this.w, this.y + this.h / 8);
context.lineTo(this.x + this.w, this.y + this.h - this.h / 8);
context.stroke();
}
于 2013-01-27T05:58:02.887 回答
1
谢谢!这正是我一直在寻找的。在我自己的代码中实现您的函数时,我进行了一些更改,例如将画布上下文作为参数传递,简化数学并让代码传递 JSLint。
function drawCylinder(ctx, x, y, w, h) {
'use strict';
var i, xPos, yPos, pi = Math.PI, twoPi = 2 * pi;
ctx.beginPath();
for (i = 0; i < twoPi; i += 0.001) {
xPos = (x + w / 2) - (w / 2 * Math.cos(i));
yPos = (y + h / 8) + (h / 8 * Math.sin(i));
if (i === 0) {
ctx.moveTo(xPos, yPos);
} else {
ctx.lineTo(xPos, yPos);
}
}
ctx.moveTo(x, y + h / 8);
ctx.lineTo(x, y + h - h / 8);
for (i = 0; i < pi; i += 0.001) {
xPos = (x + w / 2) - (w / 2 * Math.cos(i));
yPos = (y + h - h / 8) + (h / 8 * Math.sin(i));
if (i === 0) {
ctx.moveTo(xPos, yPos);
} else {
ctx.lineTo(xPos, yPos);
}
}
ctx.moveTo(x + w, y + h / 8);
ctx.lineTo(x + w, y + h - h / 8);
ctx.stroke();
}
于 2014-01-13T18:10:05.790 回答
0
如果要绘制 3D 圆柱体,最简单的方法是使用 tQuery(http://jeromeetienne.github.com/tquery/)之类的库:
var world = tQuery.createWorld().boilerplate().start();
var object = tQuery. createCylinder().addTo(world);
如果要绘制“2d”圆柱体,可以使用 canvas 2d API 绘制一个矩形,然后在其顶部绘制一个椭圆。它将显示为圆柱体。
于 2013-01-24T10:08:31.340 回答
0
var canvas = document.getElementById('canvas')
var ctx = canvas.getContext('2d');
var pos={};
const angleToRadian = function (angle) {
return Math.PI / 180 * angle;
}
var Arc = function (x, y, r, d,s) {
this.r = r;
this.x = x;
this.y = y;
// this.d=d;
ctx.beginPath();
ctx.arc(x, y, r, angleToRadian(0), angleToRadian(180));
ctx.moveTo((Number(x) + Number(r)), y);
// ctx.lineTo((Number(x) + Number(r)), d);
ctx.arc(x, y - d, r, angleToRadian(0), angleToRadian(360));
ctx.moveTo((Number(x)+Number(r)),y);
ctx.lineTo((Number(x)+Number(lX())), ((Number(y)-Number(d))+Number(r)-Number(lY())));
// ctx.moveTo((Number(x)+Number(lX())), ((Number(y)-Number(d))-Number(lY())+Number(r)));
ctx.lineTo((Number(x)+Number(lX())),(Number(y)+Number(r)-Number(lY())));
// ctx.moveTo((Number(x)+Number(lX())),(Number(y)+Number(r)-Number(lY())));
ctx.lineTo(Number(x), ((Number(y)+Number(r))-Number(d)));
// ctx.moveTo(Number(x), ((Number(y)+Number(r))-Number(d)));
ctx.lineTo(Number(x),(Number(y)+Number(r)));
// ctx.moveTo(Number(x),(Number(y)+Number(r)));
ctx.lineTo((Number(x)-Number(lX())), (Number(y)-Number(d)+Number(r)-Number(lY())));
// ctx.moveTo((Number(x)-Number(lX())), (Number(y)-Number(d)+Number(r)-Number(lY())));
ctx.lineTo((Number(x)-Number(lX())), (Number(y)+Number(r)-Number(lY())));
// ctx.moveTo((Number(x)-Number(lX())), (Number(y)+Number(r)-Number(lY())));
ctx.lineTo((Number(x)-Number(r)), (Number(y)-Number(d)));
// ctx.moveTo((Number(x)-Number(r)), (Number(y)-Number(d)));
ctx.lineTo((Number(x)-Number(r)), y);
ctx.strokeStyle = "#9c3028";
ctx.closePath();
// ctx.stroke();
ctx.fillStyle="#9b3028"
ctx.fill();
}
var lY = function () {
return Math.sqrt((Math.pow(((Math.cos(67.5 * Math.PI / 180) * this.r) * 2), 2) -
Math.pow((Math.cos(22.5 * Math.PI / 180) * (Math.cos(67.5 * Math.PI / 180) * this.r) * 2), 2)));
}
var lX = function () {
return Math.sqrt((Math.pow(((Math.cos(67.5 * Math.PI / 180) * this.r) * 2), 2) - (Math.pow(((Math.cos(67.5 * Math.PI / 180) * this.r) * 2), 2) -
Math.pow((Math.cos(22.5 * Math.PI / 180) * (Math.cos(67.5 * Math.PI / 180) * this.r) * 2), 2))));
}
document.addEventListener('mouseup',mouseUp);
document.addEventListener('mousedown',mouseDown);
document.addEventListener('mousemove',draw);
function mouseDown(e){
pos.x=e.clientX;
pos.y=e.clientY;
}
function mouseUp(e){
pos.pozX=e.clientX;
pos.pozY=e.clientY;
}
function draw(e){
if(e.buttons!==1) return;
ctx.clearRect(0,0,500,500);
Arc(pos.x, pos.y, e.clientY, e.clientX);
}
于 2019-11-22T22:06:41.480 回答