0

我是 Spring 新手，正在 MVC 中开发 Hello world 应用程序 当我从控制器返回 ModelAndView 对象时，URL 映射被搜索为相应的视图。我已经包含了所有正确的 jars。这是代码。/web -inf/sample-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">             (http://www.springframework.org/schema/context/spring-context-3.0.xsd%27%3E)
   <context:component-scan base-package="com.tcs.laks.sample.controller" />
   <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">  
         <property name="prefix" value="/WEB-INF/jsp/" />
    <property name="suffix" value=".jsp" />
</bean> </beans>

这是web.xml---

<?xml version="1.0" encoding="UTF-8"?>

  <web-app id="WebApp_ID" version="2.4"
   xmlns="http://java.sun.com/xml/ns/j2ee" 
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
   http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">    (http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd%27%3E)
   <display-name>Spring MVC Application</display-name>

   <servlet>
      <servlet-name>sample</servlet-name>
      <servlet-class>
         org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
      <load-on-startup>1</load-on-startup>
   </servlet>

   <servlet-mapping>
      <servlet-name>sample</servlet-name>
      <url-pattern>/</url-pattern>
   </servlet-mapping>

</web-app>

HelloWorldController 是..

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.portlet.ModelAndView;

@Controller
@RequestMapping("/welcome")
public class HelloWorldController {

    @RequestMapping(method = RequestMethod.GET)
    public ModelAndView helloWorld(){
    String message = "Hello";
    return new ModelAndView("hello", "message", message);
   }
}

url 给出为 //localhost:8080/sample/welcome 它给出了 404，因为它试图找到 welcome.jsp 而不是 hello.jsp

HTTP 状态 404 - /sample/WEB-INF/jsp/welcome.jsp

类型状态报告

消息 /sample/WEB-INF/jsp/welcome.jsp

描述 请求的资源 (/sample/WEB-INF/jsp/welcome.jsp) 不可用。

4

2 回答 2

1

contextConfigLocation在 web.xml 文件中为调度程序 servlet指定init-param。调度程序甚至正在读取/使用当前配置

   <servlet>
      <servlet-name>sample</servlet-name>
      <servlet-class>
         org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
      <init-param>
       <param-name>contextConfigLocation</param-name>
         <param-value>WEB-INF/sample-servlet.xml</param-value>
       </init-param>
      <load-on-startup>1</load-on-startup>
   </servlet>

   <servlet-mapping>
      <servlet-name>sample</servlet-name>
      <url-pattern>/</url-pattern>
   </servlet-mapping>

此外，您似乎已经导入了 ModelAndView 的 portlet 版本，请确保这是您想要的。如果不导入，org.springframework.web.servlet.ModelAndView

于 2013-01-24T09:54:11.090 回答
1

您使用了错误的 ModelAndView 类

import org.springframework.web.portlet.ModelAndView;

应该是

import org.springframework.web.servlet.ModelAndView;

其他一切都很好。

于 2013-01-24T10:35:34.070 回答