只是想知道 .NET 是否提供了一种干净的方法来做到这一点：
int64 x = 1000000;
string y = null;
if (x / 1024 == 0) {
y = x + " bytes";
}
else if (x / (1024 * 1024) == 0) {
y = string.Format("{0:n1} KB", x / 1024f);
}
ETC...
问问题
157329 次
26 回答
228
这是一个相当简洁的方法：
static readonly string[] SizeSuffixes =
{ "bytes", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
static string SizeSuffix(Int64 value, int decimalPlaces = 1)
{
if (decimalPlaces < 0) { throw new ArgumentOutOfRangeException("decimalPlaces"); }
if (value < 0) { return "-" + SizeSuffix(-value, decimalPlaces); }
if (value == 0) { return string.Format("{0:n" + decimalPlaces + "} bytes", 0); }
// mag is 0 for bytes, 1 for KB, 2, for MB, etc.
int mag = (int)Math.Log(value, 1024);
// 1L << (mag * 10) == 2 ^ (10 * mag)
// [i.e. the number of bytes in the unit corresponding to mag]
decimal adjustedSize = (decimal)value / (1L << (mag * 10));
// make adjustment when the value is large enough that
// it would round up to 1000 or more
if (Math.Round(adjustedSize, decimalPlaces) >= 1000)
{
mag += 1;
adjustedSize /= 1024;
}
return string.Format("{0:n" + decimalPlaces + "} {1}",
adjustedSize,
SizeSuffixes[mag]);
}
这是我建议的原始实现，它可能会稍微慢一些，但更容易理解：
static readonly string[] SizeSuffixes =
{ "bytes", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
static string SizeSuffix(Int64 value, int decimalPlaces = 1)
{
if (value < 0) { return "-" + SizeSuffix(-value, decimalPlaces); }
int i = 0;
decimal dValue = (decimal)value;
while (Math.Round(dValue, decimalPlaces) >= 1000)
{
dValue /= 1024;
i++;
}
return string.Format("{0:n" + decimalPlaces + "} {1}", dValue, SizeSuffixes[i]);
}
Console.WriteLine(SizeSuffix(100005000L));
需要记住的一件事 - 在 SI 表示法中，“kilo”通常使用小写 k，而所有较大的单位都使用大写字母。Windows 使用 KB、MB、GB，所以我在上面使用了 KB，但您可以考虑使用 kB。
于 2013-01-23T20:38:59.160 回答
117
签出ByteSize库。这是System.TimeSpan字节！
它为您处理转换和格式化。
var maxFileSize = ByteSize.FromKiloBytes(10);
maxFileSize.Bytes;
maxFileSize.MegaBytes;
maxFileSize.GigaBytes;
它还进行字符串表示和解析。
// ToString
ByteSize.FromKiloBytes(1024).ToString(); // 1 MB
ByteSize.FromGigabytes(.5).ToString(); // 512 MB
ByteSize.FromGigabytes(1024).ToString(); // 1 TB
// Parsing
ByteSize.Parse("5b");
ByteSize.Parse("1.55B");
于 2014-03-12T23:58:20.853 回答
53
我会使用Extension methods,Math.Pow函数和来解决它Enums：
public static class MyExtension
{
public enum SizeUnits
{
Byte, KB, MB, GB, TB, PB, EB, ZB, YB
}
public static string ToSize(this Int64 value, SizeUnits unit)
{
return (value / (double)Math.Pow(1024, (Int64)unit)).ToString("0.00");
}
}
并像这样使用它：
string h = x.ToSize(MyExtension.SizeUnits.KB);
于 2014-03-29T16:32:08.267 回答
43
由于其他人都在发布他们的方法，我想我会发布我通常用于此的扩展方法：
编辑：添加了 int/long 变体...并修复了 copypasta 错字...
public static class Ext
{
private const long OneKb = 1024;
private const long OneMb = OneKb * 1024;
private const long OneGb = OneMb * 1024;
private const long OneTb = OneGb * 1024;
public static string ToPrettySize(this int value, int decimalPlaces = 0)
{
return ((long)value).ToPrettySize(decimalPlaces);
}
public static string ToPrettySize(this long value, int decimalPlaces = 0)
{
var asTb = Math.Round((double)value / OneTb, decimalPlaces);
var asGb = Math.Round((double)value / OneGb, decimalPlaces);
var asMb = Math.Round((double)value / OneMb, decimalPlaces);
var asKb = Math.Round((double)value / OneKb, decimalPlaces);
string chosenValue = asTb > 1 ? string.Format("{0}Tb",asTb)
: asGb > 1 ? string.Format("{0}Gb",asGb)
: asMb > 1 ? string.Format("{0}Mb",asMb)
: asKb > 1 ? string.Format("{0}Kb",asKb)
: string.Format("{0}B", Math.Round((double)value, decimalPlaces));
return chosenValue;
}
}
于 2013-01-23T20:44:05.180 回答
16
我知道这已经是旧线程了。但也许有人会寻找解决方案。这就是我使用的最简单的方法
public static string FormatFileSize(long bytes)
{
var unit = 1024;
if (bytes < unit) { return $"{bytes} B"; }
var exp = (int)(Math.Log(bytes) / Math.Log(unit));
return $"{bytes / Math.Pow(unit, exp):F2} {("KMGTPE")[exp - 1]}B";
}
获取文件夹大小（例如用法）
public static long GetFolderSize(string path, string ext, bool AllDir)
{
var option = AllDir ? SearchOption.AllDirectories : SearchOption.TopDirectoryOnly;
return new DirectoryInfo(path).EnumerateFiles("*" + ext, option).Sum(file => file.Length);
}
示例用法：
public static void TEST()
{
string folder = @"C:\Users\User\Videos";
var bytes = GetFolderSize(folder, "mp4", true); //or GetFolderSize(folder, "mp4", false) to get all single folder only
var totalFileSize = FormatFileSize(bytes);
Console.WriteLine(totalFileSize);
}
于 2020-07-02T14:04:04.553 回答
7
投票最多的答案的简短版本存在 TB 值问题。
我对它进行了适当的调整以处理 tb 值并且仍然没有循环，并且还添加了一些对负值的错误检查。这是我的解决方案：
static readonly string[] SizeSuffixes = { "bytes", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
static string SizeSuffix(long value, int decimalPlaces = 0)
{
if (value < 0)
{
throw new ArgumentException("Bytes should not be negative", "value");
}
var mag = (int)Math.Max(0, Math.Log(value, 1024));
var adjustedSize = Math.Round(value / Math.Pow(1024, mag), decimalPlaces);
return String.Format("{0} {1}", adjustedSize, SizeSuffixes[mag]);
}
于 2013-12-28T13:39:59.277 回答
5
不。主要是因为它是一个相当小众的需求，并且有太多可能的变化。（是“KB”、“Kb”还是“Ko”？一兆字节是 1024 * 1024 字节，还是 1024 * 1000 字节？——是的，有些地方使用它！）
于 2013-01-23T20:33:39.617 回答
5
这是一个比您的更容易扩展的选项，但是不，库本身没有内置任何选项。
private static List<string> suffixes = new List<string> { " B", " KB", " MB", " GB", " TB", " PB" };
public static string Foo(int number)
{
for (int i = 0; i < suffixes.Count; i++)
{
int temp = number / (int)Math.Pow(1024, i + 1);
if (temp == 0)
return (number / (int)Math.Pow(1024, i)) + suffixes[i];
}
return number.ToString();
}
于 2013-01-23T20:35:02.407 回答
5
@Servy 的回答简洁明了。我认为它可以更简单？
private static string[] suffixes = new [] { " B", " KB", " MB", " GB", " TB", " PB" };
public static string ToSize(double number, int precision = 2)
{
// unit's number of bytes
const double unit = 1024;
// suffix counter
int i = 0;
// as long as we're bigger than a unit, keep going
while(number > unit)
{
number /= unit;
i++;
}
// apply precision and current suffix
return Math.Round(number, precision) + suffixes[i];
}
于 2018-01-26T18:44:01.473 回答
4
private string GetFileSize(double byteCount)
{
string size = "0 Bytes";
if (byteCount >= 1073741824.0)
size = String.Format("{0:##.##}", byteCount / 1073741824.0) + " GB";
else if (byteCount >= 1048576.0)
size = String.Format("{0:##.##}", byteCount / 1048576.0) + " MB";
else if (byteCount >= 1024.0)
size = String.Format("{0:##.##}", byteCount / 1024.0) + " KB";
else if (byteCount > 0 && byteCount < 1024.0)
size = byteCount.ToString() + " Bytes";
return size;
}
private void btnBrowse_Click(object sender, EventArgs e)
{
if (openFile1.ShowDialog() == DialogResult.OK)
{
FileInfo thisFile = new FileInfo(openFile1.FileName);
string info = "";
info += "File: " + Path.GetFileName(openFile1.FileName);
info += Environment.NewLine;
info += "File Size: " + GetFileSize((int)thisFile.Length);
label1.Text = info;
}
}
这也是一种方法（数字 1073741824.0 来自 1024*1024*1024 aka GB）
于 2014-08-06T06:59:50.253 回答
3
基于 NeverHopeless 的优雅解决方案：
private static readonly KeyValuePair<long, string>[] Thresholds =
{
// new KeyValuePair<long, string>(0, " Bytes"), // Don't devide by Zero!
new KeyValuePair<long, string>(1, " Byte"),
new KeyValuePair<long, string>(2, " Bytes"),
new KeyValuePair<long, string>(1024, " KB"),
new KeyValuePair<long, string>(1048576, " MB"), // Note: 1024 ^ 2 = 1026 (xor operator)
new KeyValuePair<long, string>(1073741824, " GB"),
new KeyValuePair<long, string>(1099511627776, " TB"),
new KeyValuePair<long, string>(1125899906842620, " PB"),
new KeyValuePair<long, string>(1152921504606850000, " EB"),
// These don't fit into a int64
// new KeyValuePair<long, string>(1180591620717410000000, " ZB"),
// new KeyValuePair<long, string>(1208925819614630000000000, " YB")
};
/// <summary>
/// Returns x Bytes, kB, Mb, etc...
/// </summary>
public static string ToByteSize(this long value)
{
if (value == 0) return "0 Bytes"; // zero is plural
for (int t = Thresholds.Length - 1; t > 0; t--)
if (value >= Thresholds[t].Key) return ((double)value / Thresholds[t].Key).ToString("0.00") + Thresholds[t].Value;
return "-" + ToByteSize(-value); // negative bytes (common case optimised to the end of this routine)
}
也许有过多的评论，但我倾向于留下它们以防止自己在以后的访问中犯同样的错误......
于 2018-02-09T14:06:37.103 回答
2
不。
但是你可以这样实现；
static double ConvertBytesToMegabytes(long bytes)
{
return (bytes / 1024f) / 1024f;
}
static double ConvertKilobytesToMegabytes(long kilobytes)
{
return kilobytes / 1024f;
}
于 2013-01-23T20:34:59.043 回答
2
针对 C# 9.0关系模式进行了更新
public const long OneKB = 1024;
public const long OneMB = OneKB * OneKB;
public const long OneGB = OneMB * OneKB;
public const long OneTB = OneGB * OneKB;
public static string BytesToHumanReadable(ulong bytes)
{
return bytes switch
{
(< OneKB) => $"{bytes}B",
(>= OneKB) and (< OneMB) => $"{bytes / OneKB}KB",
(>= OneMB) and (< OneGB) => $"{bytes / OneMB}MB",
(>= OneGB) and (< OneTB) => $"{bytes / OneMB}GB",
(>= OneTB) => $"{bytes / OneTB}"
//...
};
}
于 2021-06-12T04:38:25.767 回答
1
我将这里的一些答案组合成两种效果很好的方法。下面的第二种方法将从字节字符串（如 1.5.1 GB）转换回作为长类型值的字节（如 1621350140）。我希望这对寻找将字节转换为字符串并返回字节的解决方案的其他人有用。
public static string BytesAsString(float bytes)
{
string[] suffix = { "B", "KB", "MB", "GB", "TB" };
int i;
double doubleBytes = 0;
for (i = 0; (int)(bytes / 1024) > 0; i++, bytes /= 1024)
{
doubleBytes = bytes / 1024.0;
}
return string.Format("{0:0.00} {1}", doubleBytes, suffix[i]);
}
public static long StringAsBytes(string bytesString)
{
if (string.IsNullOrEmpty(bytesString))
{
return 0;
}
const long OneKb = 1024;
const long OneMb = OneKb * 1024;
const long OneGb = OneMb * 1024;
const long OneTb = OneGb * 1024;
double returnValue;
string suffix = string.Empty;
if (bytesString.IndexOf(" ") > 0)
{
returnValue = float.Parse(bytesString.Substring(0, bytesString.IndexOf(" ")));
suffix = bytesString.Substring(bytesString.IndexOf(" ") + 1).ToUpperInvariant();
}
else
{
returnValue = float.Parse(bytesString.Substring(0, bytesString.Length - 2));
suffix = bytesString.ToUpperInvariant().Substring(bytesString.Length - 2);
}
switch (suffix)
{
case "KB":
{
returnValue *= OneKb;
break;
}
case "MB":
{
returnValue *= OneMb;
break;
}
case "GB":
{
returnValue *= OneGb;
break;
}
case "TB":
{
returnValue *= OneTb;
break;
}
default:
{
break;
}
}
return Convert.ToInt64(returnValue);
}
于 2013-10-30T05:24:25.533 回答
1
我选择了 JerKimballs 解决方案，并对此表示赞同。但是，我想补充/指出，这确实是一个整体上存在争议的问题。在我的研究中（出于其他原因），我提出了以下信息。
当普通人（我听说他们存在）谈到千兆字节时，他们指的是公制系统，其中原始字节数的 1000 的 3 次方 == 千兆字节数。但是，当然有 IEC / JEDEC 标准，它在维基百科中得到了很好的总结，而不是 1000 的 x 次方，它们有 1024。对于物理存储设备（我猜逻辑如亚马逊和其他）意味着公制与 IEC 之间的差异越来越大。因此，例如 1 TB == 1 TB 公制是 1000 的 4 次方，但 IEC 官方将类似的数字称为 1 TiB，tebibyte 为 1024 的 4 次方。但是，唉，在非技术应用中（我会由观众决定）标准是公制的，目前在我自己的内部使用应用程序中，我解释了文档中的差异。但出于显示目的，我什至只提供公制。在内部，即使它在我的应用程序中不相关，我也只存储字节并进行显示计算。
作为旁注，我发现 .Net 框架 AFAIK（我经常错了，感谢强大的力量）即使在它的 4.5 化身中，在内部的任何库中都没有包含任何关于此的内容，这有点乏味。人们会期望某种开源库在某个时候成为 NuGettable，但我承认这是一个小问题。另一方面 System.IO.DriveInfo 和其他也只有字节（只要），这是相当清楚的。
于 2015-11-13T10:26:11.050 回答
1
一些递归怎么样：
private static string ReturnSize(double size, string sizeLabel)
{
if (size > 1024)
{
if (sizeLabel.Length == 0)
return ReturnSize(size / 1024, "KB");
else if (sizeLabel == "KB")
return ReturnSize(size / 1024, "MB");
else if (sizeLabel == "MB")
return ReturnSize(size / 1024, "GB");
else if (sizeLabel == "GB")
return ReturnSize(size / 1024, "TB");
else
return ReturnSize(size / 1024, "PB");
}
else
{
if (sizeLabel.Length > 0)
return string.Concat(size.ToString("0.00"), sizeLabel);
else
return string.Concat(size.ToString("0.00"), "Bytes");
}
}
然后你可以调用它：
ReturnSize(size, string.Empty);
于 2017-10-18T08:07:26.130 回答
1
我最近需要这个并且需要将字节转换为长整数。
用法：Byte.Kb.ToLong(1)应该给1024。
public enum Byte
{
Kb,
Mb,
Gb,
Tb
}
public static class ByteSize
{
private const long OneKb = 1024;
private const long OneMb = OneKb * 1024;
private const long OneGb = OneMb * 1024;
private const long OneTb = OneGb * 1024;
public static long ToLong(this Byte size, int value)
{
return size switch
{
Byte.Kb => value * OneKb,
Byte.Mb => value * OneMb,
Byte.Gb => value * OneGb,
Byte.Tb => value * OneTb,
_ => throw new NotImplementedException("This should never be hit.")
};
}
}
使用 xunit 进行测试：
[Theory]
[InlineData(Byte.Kb, 1, 1024)]
[InlineData(Byte.Kb, 2, 2048)]
[InlineData(Byte.Mb, 1, 1048576)]
[InlineData(Byte.Mb, 2, 2097152)]
[InlineData(Byte.Gb, 1, 1073741824)]
[InlineData(Byte.Gb, 2, 2147483648)]
[InlineData(Byte.Tb, 1, 1099511627776)]
[InlineData(Byte.Tb, 2, 2199023255552)]
public void ToLong_WhenConverting_ShouldMatchExpected(Byte size, int value, long expected)
{
var result = size.ToLong(value);
result.Should().Be(expected);
}
于 2020-08-29T16:01:44.310 回答
0
怎么样：
public void printMB(uint sizekB)
{
double sizeMB = (double) sizekB / 1024;
Console.WriteLine("Size is " + sizeMB.ToString("0.00") + "MB");
}
例如调用喜欢
printMB(123456);
将导致输出
"Size is 120,56 MB"
于 2014-03-29T15:56:21.073 回答
0
https://github.com/logary/logary/blob/master/src/Logary/DataModel.fs#L832-L837
let scaleBytes (value : float) : float * string =
let log2 x = log x / log 2.
let prefixes = [| ""; "Ki"; "Mi"; "Gi"; "Ti"; "Pi" |] // note the capital K and the 'i'
let index = int (log2 value) / 10
1. / 2.**(float index * 10.),
sprintf "%s%s" prefixes.[index] (Units.symbol Bytes)
（免责声明：我写了这段代码，甚至是链接中的代码！）
于 2016-12-12T17:50:12.607 回答
0
public static class MyExtension
{
public static string ToPrettySize(this float Size)
{
return ConvertToPrettySize(Size, 0);
}
public static string ToPrettySize(this int Size)
{
return ConvertToPrettySize(Size, 0);
}
private static string ConvertToPrettySize(float Size, int R)
{
float F = Size / 1024f;
if (F < 1)
{
switch (R)
{
case 0:
return string.Format("{0:0.00} byte", Size);
case 1:
return string.Format("{0:0.00} kb", Size);
case 2:
return string.Format("{0:0.00} mb", Size);
case 3:
return string.Format("{0:0.00} gb", Size);
}
}
return ConvertToPrettySize(F, ++R);
}
}
于 2017-10-12T03:05:21.073 回答
0
如上所述，在对数的帮助下，递归是最喜欢的方式。
以下函数有 3 个参数：输入、输出的维度约束，即第三个参数。
int ByteReDim(unsigned long ival, int constraint, unsigned long *oval)
{
int base = 1 + (int) log10(ival);
(*oval) = ival;
if (base > constraint) {
(*oval) = (*oval) >> 10;
return(1 + ByteReDim((*oval), constraint, oval));
} else
return(0);
}
现在让我们将 12GB 的 RAM 转换为几个单位：
int main(void)
{
unsigned long RAM;
int unit; // index of below symbols array
char symbol[5] = {'B', 'K', 'M', 'G', 'T'};
unit = ByteReDim(12884901888, 12, &RAM);
printf("%lu%c\n", RAM, symbol[unit]); // output is 12884901888B
unit = ByteReDim(12884901888, 9, &RAM);
printf("%lu%c\n", RAM, symbol[unit]); // output is 12582912K
unit = ByteReDim(12884901888, 6, &RAM);
printf("%lu%c\n", RAM, symbol[unit]); // output is 12288M
unit = ByteReDim(12884901888, 3, &RAM);
printf("%lu%c\n", RAM, symbol[unit]); // output is 12G
}
于 2017-12-15T15:19:20.503 回答
0
我将它用于 Windows（二进制前缀）：
static readonly string[] BinaryPrefix = { "bytes", "KB", "MB", "GB", "TB" }; // , "PB", "EB", "ZB", "YB"
string GetMemoryString(double bytes)
{
int counter = 0;
double value = bytes;
string text = "";
do
{
text = value.ToString("0.0") + " " + BinaryPrefix[counter];
value /= 1024;
counter++;
}
while (Math.Floor(value) > 0 && counter < BinaryPrefix.Length);
return text;
}
于 2018-06-12T08:52:36.370 回答
0
我已将此（几乎没有修改）合并到我的项目的 UWP DataBinding 转换器中，并认为它对其他人也可能有用。
代码是：
using System;
using System.Text;
using Windows.UI.Xaml.Data;
namespace MyApp.Converters
{
public class ByteSizeConverter : IValueConverter
{
static readonly string[] sSizeSuffixes = { "bytes", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
// The number of decimal places the formatter should include in the scaled output - default 1dp
public int DecimalPlaces { get; set; } = 1;
public object Convert(object value, Type targetType, object parameter, string language)
{
Int64 intVal = System.Convert.ToInt64(value);
return SizeSuffix(intVal);
}
public object ConvertBack(object value, Type targetType, object parameter, string language)
{
// TODO: Parse string into number and suffix
// Scale number by suffix multiplier to get bytes
throw new NotImplementedException();
}
string SizeSuffix(Int64 value)
{
if (this.DecimalPlaces < 0) { throw new ArgumentOutOfRangeException(String.Format("DecimalPlaces = {0}", this.DecimalPlaces)); }
if (value < 0) { return "-" + SizeSuffix(-value); }
if (value == 0) { return string.Format("{0:n" + this.DecimalPlaces + "} bytes", 0); }
// magnitude is 0 for bytes, 1 for KB, 2, for MB, etc.
int magnitude = (int)Math.Log(value, 1024);
// clip magnitude - only 8 values currently supported, this prevents out-of-bounds exception
magnitude = Math.Min(magnitude, 8);
// 1L << (magnitude * 10) == 2 ^ (10 * magnitude) [i.e. the number of bytes in the unit corresponding to magnitude]
decimal adjustedSize = (decimal)value / (1L << (magnitude * 10));
// make adjustment when the value is large enough that it would round up to 1000 or more
if (Math.Round(adjustedSize, this.DecimalPlaces) >= 1000)
{
magnitude += 1;
adjustedSize /= 1024;
}
return String.Format("{0:n" + this.DecimalPlaces + "} {1}", adjustedSize, sSizeSuffixes[magnitude]);
}
}
}
要使用它，请将本地资源添加到您的 UserControl 或 Page XAML：
<UserControl.Resources>
<converters:ByteSizeConverter x:Key="ByteFormat" DecimalPlaces="3" />
</UserControl.Resources>
在数据绑定模板或数据绑定实例中引用它：
<TextBlock HorizontalAlignment="Left" VerticalAlignment="Center"
Text="{x:Bind MyItem.FileSize_bytes, Mode=OneWay, Converter={StaticResource ByteFormat}}" />
嘿，很快。奇迹发生了。
于 2019-11-18T16:59:26.997 回答
0
这是我对@drzaus 答案的看法。我对其进行了修改，以利用舍入误差来发挥我们的优势，并正确管理单元边界周围的问题。它还处理负值。
将其C# Program放入 LinqPad：
// Kudos: https://stackoverflow.com/a/48467634/117797
void Main()
{
0.ToFriendly().Dump(); // 0 B
857.ToFriendly().Dump(); // 857 B
(173*1024).ToFriendly().Dump(); // 173 KB
(9541*1024).ToFriendly().Dump(); // 9.32 MB
(5261890L*1024).ToFriendly().Dump(); // 5.02 GB
1.ToFriendly().Dump(); // 1 B
1024.ToFriendly().Dump(); // 1 KB
1048576.ToFriendly().Dump(); // 1 MB
1073741824.ToFriendly().Dump(); // 1 GB
1099511627776.ToFriendly().Dump(); // 1 TB
1125899906842620.ToFriendly().Dump(); // 1 PB
1152921504606850000.ToFriendly().Dump(); // 1 EB
}
public static class Extensions
{
static string[] _byteUnits = new[] { "B", "KB", "MB", "GB", "TB", "PB", "EB" };
public static string ToFriendly(this int number, int decimals = 2)
{
return ((double)number).ToFriendly(decimals);
}
public static string ToFriendly(this long number, int decimals = 2)
{
return ((double)number).ToFriendly(decimals);
}
public static string ToFriendly(this double number, int decimals = 2)
{
const double divisor = 1024;
int unitIndex = 0;
var sign = number < 0 ? "-" : string.Empty;
var value = Math.Abs(number);
double lastValue = number;
while (value > 1)
{
lastValue = value;
// NOTE
// The following introduces ever increasing rounding errors, but at these scales we don't care.
// It also means we don't have to deal with problematic rounding errors due to dividing doubles.
value = Math.Round(value / divisor, decimals);
unitIndex++;
}
if (value < 1 && number != 0)
{
value = lastValue;
unitIndex--;
}
return $"{sign}{value} {_byteUnits[unitIndex]}";
}
}
输出是：
0 B
857 B
173 KB
9.32 MB
1.34 MB
5.02 GB
1 B
1 KB
1 MB
1 GB
1 TB
1 PB
1 EB
于 2020-08-25T23:37:40.893 回答
0
string Convert(float bytes)
{
string[] Group = { "Bytes", "KB", "MB", "GB", "TB"};
float B = bytes; int G = 0;
while (B >= 1024 && G < 5)
{
B /= 1024;
G += 1;
}
float truncated = (float)(Math.Truncate((double)B * 100.0) / 100.0);
string load = (truncated + " " + Group[G]);
return load;
}
于 2021-03-22T09:12:31.707 回答
0
我就是这样做的。
Console.Write(FileSizeInBytes > 1048576 ? FileSizeInBytes / 1048576f + " MB" : FileSizeInBytes / 1024f + " KB"); //1048576 = 1024 * 1024
于 2021-10-08T06:21:51.183 回答