3

我正在尝试创建一个使用 REST 将数据传递给客户端的 Web 服务。我现在遇到两个问题，一个在客户端，一个在服务器端。我一直在尝试很多事情，但我比以前更加卡住了。我希望你们中的任何人都可以帮助我。

我尝试通过浏览器并通过应用程序接近 Web 服务。如果我直接通过 URL 访问服务器，则会收到以下错误消息：

SEVERE: A message body writer for Java class java.util.ArrayList, and Java type java.util.Collection<domain.Tweet>, and MIME media type text/plain was not found
SEVERE: The registered message body writers compatible with the MIME media type are:
text/plain ->
  com.sun.jersey.core.impl.provider.entity.StringProvider
  com.sun.jersey.core.impl.provider.entity.ReaderProvider
*/* ->
  com.sun.jersey.core.impl.provider.entity.FormProvider
  com.sun.jersey.core.impl.provider.entity.MimeMultipartProvider
  com.sun.jersey.core.impl.provider.entity.StringProvider
  com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
  com.sun.jersey.core.impl.provider.entity.FileProvider
  com.sun.jersey.core.impl.provider.entity.InputStreamProvider
  com.sun.jersey.core.impl.provider.entity.DataSourceProvider
  com.sun.jersey.core.impl.provider.entity.XMLJAXBElementProvider$General
  com.sun.jersey.core.impl.provider.entity.ReaderProvider
  com.sun.jersey.core.impl.provider.entity.DocumentProvider
  com.sun.jersey.core.impl.provider.entity.StreamingOutputProvider
  com.sun.jersey.core.impl.provider.entity.SourceProvider$SourceWriter
  com.sun.jersey.server.impl.template.ViewableMessageBodyWriter
  com.sun.jersey.json.impl.provider.entity.JSONJAXBElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONArrayProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONObjectProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONWithPaddingProvider
  com.sun.jersey.core.impl.provider.entity.XMLRootElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLListElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONRootElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONListElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JacksonProviderProxy
  com.sun.jersey.moxy.MoxyMessageBodyWorker
  com.sun.jersey.moxy.MoxyListMessageBodyWorker

如果我运行客户端应用程序，我会收到以下错误消息：

Exception in thread "AWT-EventQueue-0" com.sun.jersey.api.client.UniformInterfaceException: GET http://localhost:8080/KwetterSOAP/resources/rest/user/Hans/tweets returned a response status of 500 Internal Server Error
    at com.sun.jersey.api.client.WebResource.handle(WebResource.java:688)
    at com.sun.jersey.api.client.WebResource.access$300(WebResource.java:74)
    at com.sun.jersey.api.client.WebResource$Builder.get(WebResource.java:508)
    at service.RestClient.getTweets(RestClient.java:52)
    at kwettermonitor.KwetterFollowing.btnZoekFollowersActionPerformed(KwetterFollowing.java:103)
    at kwettermonitor.KwetterFollowing.access$000(KwetterFollowing.java:20)
    at kwettermonitor.KwetterFollowing$1.actionPerformed(KwetterFollowing.java:54)
    at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:2018)
    at javax.swing.AbstractButton$Handler.actionPerformed(AbstractButton.java:2341)
    at javax.swing.DefaultButtonModel.fireActionPerformed(DefaultButtonModel.java:402)
    at javax.swing.DefaultButtonModel.setPressed(DefaultButtonModel.java:259)
    at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(BasicButtonListener.java:252)
    at java.awt.Component.processMouseEvent(Component.java:6505)
    at javax.swing.JComponent.processMouseEvent(JComponent.java:3321)
    at java.awt.Component.processEvent(Component.java:6270)
    at java.awt.Container.processEvent(Container.java:2229)
    at java.awt.Component.dispatchEventImpl(Component.java:4861)
    at java.awt.Container.dispatchEventImpl(Container.java:2287)
    at java.awt.Component.dispatchEvent(Component.java:4687)
    at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:4832)
    at java.awt.LightweightDispatcher.processMouseEvent(Container.java:4492)
    at java.awt.LightweightDispatcher.dispatchEvent(Container.java:4422)
    at java.awt.Container.dispatchEventImpl(Container.java:2273)
    at java.awt.Window.dispatchEventImpl(Window.java:2713)
    at java.awt.Component.dispatchEvent(Component.java:4687)
    at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:707)
    at java.awt.EventQueue.access$000(EventQueue.java:101)
    at java.awt.EventQueue$3.run(EventQueue.java:666)
    at java.awt.EventQueue$3.run(EventQueue.java:664)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:87)
    at java.awt.EventQueue$4.run(EventQueue.java:680)
    at java.awt.EventQueue$4.run(EventQueue.java:678)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.awt.EventQueue.dispatchEvent(EventQueue.java:677)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:211)
    at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:128)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:117)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:113)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:105)
    at java.awt.EventDispatchThread.run(EventDispatchThread.java:90)

Web服务已创建如下：

@Path("/rest")
@Stateless
public class RESTService {

    @Inject @Named(value = "kwetterService")
    private KwetterService service;

    @GET
    @Path("/user/{user}")
    @Produces(MediaType.TEXT_PLAIN)
    public User getUser(@PathParam("user") String userName)
    {
        return service.findByName(userName);
    }

    @GET
    @Path("/user/{user}/tweets")
    @Produces(MediaType.TEXT_PLAIN)
    public Collection<Tweet> getTweets(@PathParam("user") String userName)
    {
        System.out.println("Service: " + service);
        User user = service.findByName(userName);
        System.out.println(userName);
        System.out.println(user);
        return user.getTweets();
    }

客户端如下：

public class RestClient {
    private WebResource webResource;
    private Client client;
    private static final String BASE_URI = "http://localhost:8080/KwetterSOAP/resources";

    public RestClient() {
        DefaultClientConfig config = new DefaultClientConfig();
        client = Client.create(config);
        webResource = client.resource(BASE_URI).path("rest");
    }

    public User getUser(String userName) throws UniformInterfaceException {
        final WebResource.Builder userResource = webResource
           .path(String.format("/user/%s", userName))
           .accept(MediaType.TEXT_PLAIN) ;
        return userResource.get(User.class);
    }

    public Collection<Tweet> getTweets(String userName) throws UniformInterfaceException {
        final WebResource.Builder tweetResource = webResource
           .path(String.format("/user/%s/tweets", userName))
           .accept(MediaType.TEXT_PLAIN);
        return tweetResource.get(new GenericType<Collection<Tweet>>(){});
    }

我也有点困惑的是，在哪里放置 @XML... 注释。我已将服务注释为根元素：

@Named(value = "kwetterService")
@Stateless
@XmlRootElement
public class KwetterService {

我没有注释使用的方法：

public User findByName(String name)
    {
        return userDAO.getUser(name);
    }

UserDAO 处理数据库中的数据。我在这里没有为 REST/XML 添加任何内容。我也将 User 设为 XMLRootElement：

@Entity
@XmlRootElement
@Table(name="Users")
public class User implements Serializable {

在 getTweets() 方法中，我添加了 XMLElement 注释：

@XmlElement
    public Collection<Tweet> getTweets() {
        List<Tweet> temp = new ArrayList<Tweet>(tweets);
        Collections.reverse(temp);
        return temp;
    }

我自己的猜测是我对方法和类的整个注释是错误的。你能看到任何错误吗？

4

1 回答 1

6

请记住，JAX-RS 的核心是建立在 HTTP 之上，而 HTTP 不知道也不关心 Java 对象。当您从资源方法返回对象时，必须将它们转换为请求客户端可以使用的数据。此翻译由名为MessageBodyWriters的实体完成，并且所有 JAX-RS 实现都需要附带一组预打包的实体。不幸的是，没有要求实现能够将您的对象转换为 TEXT_PLAIN。从您发布的堆栈跟踪中，您实际上可以看到没有提供者能够处理该媒体类型：

com.sun.jersey.core.impl.provider.entity.FormProvider
com.sun.jersey.core.impl.provider.entity.MimeMultipartProvider
com.sun.jersey.core.impl.provider.entity.StringProvider
com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
com.sun.jersey.core.impl.provider.entity.FileProvider
com.sun.jersey.core.impl.provider.entity.InputStreamProvider
com.sun.jersey.core.impl.provider.entity.DataSourceProvider
com.sun.jersey.core.impl.provider.entity.XMLJAXBElementProvider$General
com.sun.jersey.core.impl.provider.entity.ReaderProvider
com.sun.jersey.core.impl.provider.entity.DocumentProvider
com.sun.jersey.core.impl.provider.entity.StreamingOutputProvider
com.sun.jersey.core.impl.provider.entity.SourceProvider$SourceWriter

但是，所有 JAX-RS 实现必须提供的一种转换是从 Java 对象到 XML。所以你可以安全地使用它作为你的数据格式。仅显示更改，您需要合并到现有代码中：

Java 豆：

@Entity
@XmlRootElement
@Table(name="Users")
public class User implements Serializable {

    @XmlWrapperElement("tweets")
    public Collection<Tweet> getTweets() {
        List<Tweet> temp = new ArrayList<Tweet>(tweets);
        Collections.reverse(temp);
        return temp;
    }
}

服务器：

@Path("/rest")
@Stateless
public class RESTService {
    @GET
    @Path("/user/{user}")
    @Produces(MediaType.APPLICATION_XML)
    public User getUser(@PathParam("user") String userName);

    @GET
    @Path("/user/{user}/tweets")
    @Produces(MediaType.APPLICATION_XML)
    public Collection<Tweet> getTweets(@PathParam("user") String userName);
}

客户：

public class RestClient {
    public User getUser(String userName) throws UniformInterfaceException {
        final WebResource.Builder userResource = webResource
           .path(String.format("/user/%s", userName))
           .accept(MediaType.APPLICATION_XML) ;
        return userResource.get(User.class);
    }

    public Collection<Tweet> getTweets(String userName)
        throws UniformInterfaceException {
        final WebResource.Builder tweetResource = webResource
           .path(String.format("/user/%s/tweets", userName))
           .accept(MediaType.APPLICATION_XML);
        return tweetResource.get(new GenericType<Collection<Tweet>>(){});
    }
}
于 2013-01-23T19:51:28.733 回答