我一直在看一个关于如何通过 rasp pi 发送短信的教程。这是我拥有的代码,我不确定为什么会出错。
#!/usr/bin/python
#-----------------------------------
# Send SMS Text Message
#
# Author : Matt Hawkins
# Site : http://www.raspberrypi-spy.co.uk/
# Date : 30/08/2012
#
# Requires account with TxtLocal
# http://www.txtlocal.co.uk/?tlrx=114032
#
#-----------------------------------
# Import required libraries
import urllib # URL functions
import urllib2 # URL functions
# Define your message
message = 'Test message sent from my Raspberry Pi'
# Set your username and sender name.
# Sender name must alphanumeric and
# between 3 and 11 characters in length.
username = 'jonfdom1@aol.com'
sender = 'Jonny.D'
# Your unique hash is available from the docs page
# https://control.txtlocal.co.uk/docs/
hash = '8fe5dae7bafdbbfb00c7aebcfb24e005b5cb7be8'
# Set the phone number you wish to send
# message to.
# The first 2 digits are the country code.
# 44 is the country code for the UK
# Multiple numbers can be specified if required
# e.g. numbers = ('447xxx123456','447xxx654321')
numbers = ('447xxxxxx260')
# Set flag to 1 to simulate sending
# This saves your credits while you are
# testing your code.
# To send real message set this flag to 0
test_flag = 1
#-----------------------------------
# No need to edit anything below this line
#-----------------------------------
values = {'test' : test_flag,
'uname' : username,
'hash' : hash,
'message' : message,
'from' : sender,
'selectednums' : numbers }
url = 'http://www.txtlocal.com/sendsmspost.php'
postdata = urllib.urlencode(values)
req = urllib2.Request(url, postdata)
print 'Attempt to send SMS ...'
try:
response = urllib2.urlopen(req)
response_url = response.geturl()
if response_url==url:
print 'SMS sent!'
except urllib2.URLError, e:
print 'Send failed!'
print e.reason
这是我在终端上弹出的错误消息
File "send_sms.py", line 331
response = urllib2.urlopen(req)
^
IndentationError: expected an indented block