1

我在 mysql 表中有一堆列,其名称以“X_”开头(例如:X_N、X_Pad、X_Server 等)。现在,这些列可以为空。

我想找出以'X_'开头的列最不为NULL。

4

3 回答 3

3

COUNT(expr)

返回 SELECT 语句检索的行中 expr 的非 NULL 值的计数。

以下查询将为每列返回非空计数:

SELECT
COUNT(*)     AS Total,
COUNT(X_N)   AS NNC_N,
COUNT(X_Pad) AS NNC_Pad
FROM table;

您可以使用此查询从表中获取匹配列的列表:

SELECT COLUMN_NAME
FROM  INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = '<database_name>'
AND   TABLE_NAME = '<table_name>'
AND   COLUMN_NAME LIKE 'x\_%';

-- Output:
-- X_N
-- X_Pad
-- X_Server

您可以使用此查询来构建查询:

SELECT CONCAT('SELECT ', GROUP_CONCAT('COUNT(`', COLUMN_NAME, '`) AS `NNC of ', COLUMN_NAME, '`'), ' FROM `', TABLE_NAME, '`')
FROM  INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = '<database_name>'
AND   TABLE_NAME = '<table_name>'
AND   COLUMN_NAME LIKE 'x\_%';

-- Output (added whitespace for readability):
-- SELECT
-- COUNT(`X_N`)      AS `NNC of X_N`,
-- COUNT(`X_Pad`)    AS `NNC of X_Pad`,
-- COUNT(`X_Server`) AS `NNC of X_Server`
-- FROM `<table_name>`

备用:

SELECT GROUP_CONCAT('SELECT \'', COLUMN_NAME, '\' AS `Col`, COUNT(`', COLUMN_NAME , '`) AS `NNC` FROM `', TABLE_NAME , '`' SEPARATOR ' UNION ALL ')
FROM  INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = '<database_name>'
AND   TABLE_NAME = '<table_name>'
AND   COLUMN_NAME LIKE 'x\_%';

-- Output (added whitespace for readability):
-- SELECT 'X_N'      AS `Col`, COUNT(`X_N`)      AS `NNC` FROM `<table_name>` UNION ALL 
-- SELECT 'X_Pad'    AS `Col`, COUNT(`X_Pad`)    AS `NNC` FROM `<table_name>` UNION ALL 
-- SELECT 'X_Server' AS `Col`, COUNT(`X_Server`) AS `NNC` FROM `<table_name>`
于 2013-01-23T08:50:10.863 回答
1

从 db.tbl 中选择计数(X_N)、计数(X_Pad)、计数(X_Server);

可以的。

如果你只需要一个方法来生成这个 SQL,你可以使用

SELECT CONCAT("select ", GROUP_CONCAT("count(",column_name, ")"), " from ", table_schema, '.', table_name)
FROM information_schema.columns
WHERE table_schema='db' AND table_name='tbl' AND column_name LIKE 'X\_%';
于 2013-01-23T09:21:58.223 回答
0

大概是这样的?(未经测试)

SELECT 
(SELECT COUNT(id) FROM My_Table WHERE X_1 != NULL) as x1,
(SELECT COUNT(id) FROM My_Table WHERE X_2 != NULL) as x2,
(SELECT COUNT(id) FROM My_Table WHERE X_3 != NULL) as x3,
(SELECT COUNT(id) FROM My_Table WHERE X_4 != NULL) as x4;
于 2013-01-23T08:45:49.507 回答