我无法打开文件 (amount2.csv) 进行更改、保存并关闭文件。
如何打开文件编辑、保存和关闭它?
import csv
changes = {
'1 dozen' : '12'
}
with open('amount2.csv', 'r') as f:
reader = csv.reader(f)
print f
f.close()
我的错误:在 0x1004656f0 打开文件“amount2.csv”,模式“r”(<> 已删除)
我无法打开文件 (amount2.csv) 进行更改、保存并关闭文件。
如何打开文件编辑、保存和关闭它?
import csv
changes = {
'1 dozen' : '12'
}
with open('amount2.csv', 'r') as f:
reader = csv.reader(f)
print f
f.close()
我的错误:在 0x1004656f0 打开文件“amount2.csv”,模式“r”(<> 已删除)
这
<open file 'amount2.csv', mode 'r' at 0x1004656f0>
您看到的不是错误,而是“打印 f”的结果。要查看文件的内容,您可以这样做
with open('test.csv', 'rb') as f:
reader = csv.reader(f)
for row in reader:
# row is a list of strings
# use string.join to put them together
print ', '.join(row)
要将行附加到您的文件中,请改为
changes = [
['1 dozen','12'],
['1 banana','13'],
['1 dollar','elephant','heffalump'],
]
with open('test.csv', 'ab') as f:
writer = csv.writer(f)
writer.writerows(changes)
Python CSV 文档中的更多信息
编辑:
一开始我误解了,你想在你的 csv 文件中将“1打”的所有条目更改为“12”。我首先要说的是,不使用 csv 模块更容易做到这一点,但这里有一个使用它的解决方案。
import csv
new_rows = [] # a holder for our modified rows when we make them
changes = { # a dictionary of changes to make, find 'key' substitue with 'value'
'1 dozen' : '12', # I assume both 'key' and 'value' are strings
}
with open('test.csv', 'rb') as f:
reader = csv.reader(f) # pass the file to our csv reader
for row in reader: # iterate over the rows in the file
new_row = row # at first, just copy the row
for key, value in changes.items(): # iterate over 'changes' dictionary
new_row = [ x.replace(key, value) for x in new_row ] # make the substitutions
new_rows.append(new_row) # add the modified rows
with open('test.csv', 'wb') as f:
# Overwrite the old file with the modified rows
writer = csv.writer(f)
writer.writerows(new_rows)
如果您是编程和 python 新手,最麻烦的可能是
new_row = [ x.replace(key, value) for x in new_row ]
但这只是一个列表推导,实际上等效于
temp = []
for x in new_row:
temp.append( x.replace(key, value) )
new_row = temp
您正在尝试打印文件对象本身,这不会有多大用处。您是否查看过 CSV 模块的文档?第一个代码示例向您展示了如何使用 csv.reader。