12

我有一些函数可以在画布元素上绘制矩形。绘制元素时，我希望能够通过拖动它的角来调整它的大小。

var canvas = document.getElementById('canvas'),
  ctx = canvas.getContext('2d'),
  rect = {},
  drag = false;

function init() {
  canvas.addEventListener('mousedown', mouseDown, false);
  canvas.addEventListener('mouseup', mouseUp, false);
  canvas.addEventListener('mousemove', mouseMove, false);
}

function mouseDown(e) {
  rect.startX = e.pageX - this.offsetLeft;
  rect.startY = e.pageY - this.offsetTop;
  drag = true;
}

function mouseUp() {
  drag = false;
}

function mouseMove(e) {
  if (drag) {
    rect.w = (e.pageX - this.offsetLeft) - rect.startX;
    rect.h = (e.pageY - this.offsetTop) - rect.startY;
    ctx.clearRect(0, 0, canvas.width, canvas.height);
    draw();
  }
}

function draw() {
  ctx.fillRect(rect.startX, rect.startY, rect.w, rect.h);
}

init();
<canvas id="canvas" width="500" height="500"></canvas>

4

2 回答 2

24

确保使用某种阈值来检查角上的拖动，使用closeEnough变量来保持此阈值，然后通过查看角点和鼠标点之间的差值的绝对值是否小于阈值来检查角。除此之外，还有很多案例需要处理。这是它的一个jsFiddle

var canvas = document.getElementById('canvas'),
    ctx = canvas.getContext('2d'),
    rect = {},
    drag = false,
    mouseX, 
    mouseY,
    closeEnough = 10,
    dragTL=dragBL=dragTR=dragBR=false;

function init() {
  canvas.addEventListener('mousedown', mouseDown, false);
  canvas.addEventListener('mouseup', mouseUp, false);
  canvas.addEventListener('mousemove', mouseMove, false);
}

function mouseDown(e) {
  mouseX = e.pageX - this.offsetLeft;
  mouseY = e.pageY - this.offsetTop;

  // if there isn't a rect yet
  if(rect.w === undefined){
    rect.startX = mouseY;
    rect.startY = mouseX;
    dragBR = true;
  }

  // if there is, check which corner
  //   (if any) was clicked
  //
  // 4 cases:
  // 1. top left
  else if( checkCloseEnough(mouseX, rect.startX) && checkCloseEnough(mouseY, rect.startY) ){
    dragTL = true;
  }
  // 2. top right
  else if( checkCloseEnough(mouseX, rect.startX+rect.w) && checkCloseEnough(mouseY, rect.startY) ){
    dragTR = true;

  }
  // 3. bottom left
  else if( checkCloseEnough(mouseX, rect.startX) && checkCloseEnough(mouseY, rect.startY+rect.h) ){
    dragBL = true;

  }
  // 4. bottom right
  else if( checkCloseEnough(mouseX, rect.startX+rect.w) && checkCloseEnough(mouseY, rect.startY+rect.h) ){
    dragBR = true;

  }
  // (5.) none of them
  else {
    // handle not resizing
  }

  ctx.clearRect(0,0,canvas.width,canvas.height);
  draw();

}

function checkCloseEnough(p1, p2){
  return Math.abs(p1-p2)<closeEnough;
}
function mouseUp() {
  dragTL = dragTR = dragBL = dragBR = false;
}

function mouseMove(e) {
  mouseX = e.pageX - this.offsetLeft;
  mouseY = e.pageY - this.offsetTop;
  if(dragTL){
    rect.w += rect.startX-mouseX;
    rect.h += rect.startY-mouseY;
    rect.startX = mouseX;
    rect.startY = mouseY;
  } else if(dragTR) {
    rect.w = Math.abs(rect.startX-mouseX);
    rect.h += rect.startY-mouseY;
    rect.startY = mouseY;
  } else if(dragBL) {
    rect.w += rect.startX-mouseX;
    rect.h = Math.abs(rect.startY-mouseY);
    rect.startX = mouseX;  
  } else if(dragBR) {
    rect.w = Math.abs(rect.startX-mouseX);
    rect.h = Math.abs(rect.startY-mouseY);
  }
    ctx.clearRect(0,0,canvas.width,canvas.height);
    draw();
}

function draw() {
  ctx.fillRect(rect.startX, rect.startY, rect.w, rect.h);
}

init();
于 2013-01-23T01:36:44.690 回答
14

做一个手柄系统：当鼠标移动时，获取到每个角的距离以获取光标附近的第一个角，然后保存它并根据它调整矩形的大小。

这是一个说明它的 JSfiddle：http: //jsfiddle.net/BaliBalo/9HXMG/

function getHandle(mouse) {
    if (dist(mouse, point(rect.x, rect.y)) <= handlesSize) return 'topleft';
    if (dist(mouse, point(rect.x + rect.w, rect.y)) <= handlesSize) return 'topright';
    if (dist(mouse, point(rect.x, rect.y + rect.h)) <= handlesSize) return 'bottomleft';
    if (dist(mouse, point(rect.x + rect.w, rect.y + rect.h)) <= handlesSize) return 'bottomright';
    if (dist(mouse, point(rect.x + rect.w / 2, rect.y)) <= handlesSize) return 'top';
    if (dist(mouse, point(rect.x, rect.y + rect.h / 2)) <= handlesSize) return 'left';
    if (dist(mouse, point(rect.x + rect.w / 2, rect.y + rect.h)) <= handlesSize) return 'bottom';
    if (dist(mouse, point(rect.x + rect.w, rect.y + rect.h / 2)) <= handlesSize) return 'right';
    return false;
}
于 2013-01-23T02:16:04.200 回答