假设我有一个年龄列表（代表一个国家的预期寿命）：
ages= ['70.37668898', '72.15779044', '73.25278702', '72.18979793', '80.73137673','55.43124818' '54.16265064', '54.16540964', ...]
现在我的预期寿命范围增加了两倍（范围 48-100），如下所示：
48-50,50-52, ...., 98-100
我想创建一个新列表，其中包含每个年龄段的列表。如果给定的年龄在预期寿命范围内，则内部列表包含 1，否则为 0。
所以结果看起来像这样：
每个内部列表都属于年龄范围内的一个年龄
[[0,0,0,0,1, ..., 0],[0,1,0,0,0, ..., 0],...]
我怎样才能做到这一点？
您的范围结构有点模糊。让我们假设你的范围是这样的
ranges = [(48,50),(50,52),...(98,100)]
现在
ages= ['70.37668898', '72.15779044', '73.25278702', '72.18979793', '80.73137673','55.43124818' '54.16265064', '54.16540964', ...]
result = [ [ 1 if (r[0] <= age <= r[1]) else 0 for r in ranges] for age in ages]
或者，如果您的范围是固定的，从 50 到 100 以 2 为增量，您可以使用生成器：
result = [ [ 1 if (r[0] <= age <= r[1]) else 0 for r in ( (i-2,i) for i in range(50,100,2)) ] for age in ages]
ages = [70.37668898, 72.15779044, 73.25278702, 72.18979793, 80.73137673, 55.43124818, 54.16265064, 54.16540964]
[[int(age >= 48+2*i and age <50+2*i) for i in range(25)] for age in ages]
结果是
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
这（也许）是你问的。