-1

我对 C# 和面向对象的编程都很陌生。我试图弄清楚为什么这个程序无法编译。这是给我带来麻烦的代码片段：

static void AdvancePreLvlThree() // advances player to next level when level is less than three
{
    if(level == 1)
    {
        xp = (xp - 100); // carries remaining xp over to next level
    }
    else if(level == 2)
    {
        xp = (xp - 150);
    }

    level +=1; // advances
    return Update(); // checks again to see if they can advance further
}

完整程序：

///////////////////////////////////////////////////////
//
// A namespace/program for managing experience points 
// and determining if the player can level up.
//
// Written by Jared Beach
// January 19, 2013
//
//////////////////////////////////////////////////////

using System;
namespace LevelSystem
{
    public class LevelSystem 
    {
        public void LevelStorage()
        {
            int level = 1; // stores player level
        }

        public void XPStorage()
        {
            int xp = 0; // stores player xp
        }

        public void XPRequirement() // xp required to advance to the next level
        {
            int maxXP = (8 * level^3);

        static void AdvancePreLvlThree() // advances player to next level when level is less than three
        {
            if(level == 1)
            {
                xp = (xp - 100); // carries remaining xp over to next level
            }
            else if(level == 2)
            {
                xp = (xp - 150);
            }

            level +=1; // advances
            return Update(); // checks again to see if they can advance further
        }

        static void Advance() // advances player to next level
        {
            xp = (level - maxXP); // carries remaining xp over to next level
            level +=1;
            return Update();
        }

        static void Update() // checks to see if player can advance levels
        {
            if(level == 1 && xp > 100) // special case to keep basic progression ratio close to one
            {
                AdvancePreLvlThree();
            }
            else if(level == 3 && xp > 150)
            {
                AdvancePreLvlThree();
            }
            else if(xp >= 3 && xp > maxXP) 
            {
               return Advance();
            }
        }
    }

    public class Program
    {
        static void Main(string[] args)
        {

        }
    }
}

我得到的错误是：

Program.cs(30,8): error CS1525: Unexpected symbol `static'
Program.cs(30,16): error CS1547: Keyword `void' cannot be used in this context
Program.cs(30,38): error CS1525: Unexpected symbol `('
Program.cs(36,16): error CS1519: Unexpected symbol `else' in class, struct, or interface member declaration
Program.cs(36,28): error CS1519: Unexpected symbol `==' in class, struct, or interface member declaration
Program.cs(38,20): error CS1519: Unexpected symbol `=' in class, struct, or interface member declaration
Program.cs(38,26): error CS1519: Unexpected symbol `-' in class, struct, or interface member declaration
Program.cs(41,12): error CS1525: Unexpected symbol `level'

如果相关的话，它与我的 Main 不在同一个班级。

4

2 回答 2

3

正如其他人所说，您需要在这种情况下显示所有代码，因为这听起来像是您的代码中缺少/错误的其他内容并在此时中断。这是一个您正在尝试做的工作示例，尽管它看起来不是一个很好的方法，有很多static项目，您应该真正研究面向对象编程！

namespace ConsoleApplication1
{
    class Program
    {
        private static int level = 0;
        private static int xp = 0;

        static void Main(string[] args)
        {
            AdvancePreLvlThree();
        }

        static bool AdvancePreLvlThree() // advances player to next level when level is less than three
        {
            if(level == 1)
            {
                xp = (xp - 100); // carries remaining xp over to next level
            }
            else if(level == 2)
            {
                xp = (xp - 150);
            }

            level +=1; // advances
            return Update(); // checks again to see if they can advance further
        }

        static bool Update()
        {
            // Yes they can...
            return true;
        }
    }
}

我已经让你的AdvancePreLvlThree方法返回一个布尔值，因为这是你试图做的，但该方法被标记为无效？无论如何，希望这会让你开始？

于 2013-01-22T15:42:11.597 回答
1

一些事情，

  1. 您的方法被声明为 void，并且它返回更新，因此使该方法的返回类型与更新相同。
  2. 如果您的方法与 main 不在同一个类中，则将方法设为 public，在包含 main 的类中引用新类。
  3. 在使用它们之前将 XP 和 level 声明为 vairables，在方法级别范围内声明它们。
  4. 此方法应与更新在同一类中。
于 2013-01-22T15:46:38.930 回答