我编写了一个简单的 C 代码,它使用引擎根据用户输入运行两种不同的算法。它使用指向算法方法和对象的函数指针。在某处我无法追踪到一个令人讨厌的内存错误,所以也许我以错误的方式分配内存。出了什么问题?
下面是(相关部分)代码的最小工作示例。
主程序
#include "engine.h"
int main()
{
char *id = "one";
Engine_t eng;
Engine_init(&eng);
Engine_select_algorithm(eng, id);
Engine_run(eng);
}
引擎.h
typedef struct _Engine *Engine_t;
引擎.c
#include "engine.h"
#include "algorithm_one.h"
#include "algorithm_two.h"
typedef struct _Engine
{
void *p_algorithm;
void (*init)(Engine_t);
void (*run)(Engine_t);
} Engine;
void Engine_init(Engine_t *eng)
{
*eng = malloc(sizeof(Engine));
(*eng)->p_algorithm = NULL;
}
void Engine_select_algorithm(Engine_t eng, char *id)
{
if ( strcmp(id, "one") == 0 )
{
eng->init = Algorithm_one_init;
eng->run = Algorithm_one_run;
}
else if ( strcmp(id, "two") == 0 )
{
eng->init = Algorithm_two_init;
eng->run = Algorithm_two_run;
}
else
{
printf("Unknown engine %s.\n", id); exit(0);
}
eng->init(eng);
}
void Engine_run(Engine_t eng)
{
eng->run(eng);
}
void Engine_set_algorithm(Engine_t eng, void *p)
{
eng->p_algorithm = p;
}
void Engine_get_algorithm(Engine_t eng, void *p)
{
p = eng->p_algorithm;
}
算法_one.h
typedef struct _A_one *A_one_t;
algorithm_one.c
#include "engine.h"
#include "algorithm_one.h"
typedef struct _A_one
{
float value;
} A_one;
void Algorithm_one_init(Engine_t eng)
{
A_one_t aone;
aone = malloc(sizeof(A_one));
aone->value = 13.0;
//int var = 10;
Engine_set_algorithm(eng, &aone);
}
void Algorithm_one_run(Engine_t eng)
{
A_one_t aone;
Engine_get_algorithm(eng, &aone);
printf("I am running algorithm one with value %f.\n", aone->value);
// The code for algorithm one goes here.
}
algorithm_two.h和algorithm_two.c的代码与算法一文件相同。
一定存在内存错误,因为代码按给定的方式运行,但如果我取消注释
//int var = 10;
algoritm_one.c中的行代码因分段错误而崩溃。