mysql - mysql join 上的歧义子句

Question

我正在尝试加入 2 个表以获取匹配值，但得到了模棱两可的子句，

我的代码在这里

SELECT *
FROM auction_media
  JOIN auctions
    ON auction_id = auction_id
    WHERE media_type = '3'

可以在此处找到我的表结构的示例错误是 on 子句中的 Column 'auction_id' is ambiguous

http://sqlfiddle.com/#!2/13583

我应该怎么做才能解决这个问题？

Answer 1

试试这个

SELECT *
FROM auction_media
JOIN auctions
ON auction_media.auction_id = auctions.auction_id
WHERE media_type = '3'

Answer 2

SELECT *
FROM auction_media
  JOIN auctions
    ON auction_media.auction_id = auctions.auction_id
    WHERE media_type = '3'

Answer 3

你需要给你的表起别名。问题是因为多个列具有相同的名称，在这种情况下是您尝试加入的列。尝试

SELECT * 
FROM auction_media AS am
    JOIN auctions AS a
    ON am.auction_id = a.auction_id
    WHERE media_type = '3'

更新：我给它们起了别名以使其更短且更易读，但另一种选择是使用完整的 table.column 名称，例如auction_media.auction_id

或者您可以改用“使用”

SELECT * 
FROM auction_media
    JOIN auctions
    USING (auction_id)
    WHERE media_type = '3'

Answer 4

SELECT *
FROM auction_media
  JOIN auctions
    ON auction_media.auction_id = auctions.auction_id
    WHERE media_type = '3'

Answer 5

只需根据表名引用列名。

SELECT * FROM auction_media am JOIN auction a ON am.auction_id = a.auction_id
WHERE media_type = '3'

Answer 6

这样做：

SELECT * FROM auction_media JOIN auctions ON auction_media.auction_id = auctions.auction_id WHERE media_type = '3'

阅读SQL JOIN