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我正在开发一个在线考勤卡系统，但遇到了障碍。我需要做的是在每一行中计算员工可能每天多次进出的日期和日期timeIn。timeOut我有一个工作查询来查找一整天的总数，但不是每一行。我已经包含了数据库表的结构以及我希望看到的一些示例。

+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+
| id | employeeID | date     | timeIn  | jobDescription               | equipType   | unitNumber | unitHours | timeOut  |
+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+
|  8 |          1 | 01/15/13 | 7:00 AM | Loaded sand in Jefferson     | Excavator   | 345        |      NULL | 9:30 PM  |
|  9 |          1 | 01/15/13 | 10:00 AM | Loaded sand in Jefferson     | Excavator   | 345        |      NULL | 12:00 PM |
| 10 |          1 | 01/16/13 | 7:00 AM | Loaded sand in Jefferson     | Excavator   | 345        |      NULL | 5:30 PM  |
| 11 |          1 | 01/17/13 | 7:00 AM | Loaded sand in Jefferson     | Excavator   | 345        |      NULL | 5:30 PM  |
| 12 |          1 | 01/18/13 | 8:00 AM | Backfill in Whispering Creek | Skid Loader | 297        |      NULL | 5:30 PM  |
| 13 |          1 | 01/19/13 | 8:00 AM | Backfill in Whispering Creek | Skid Loader | 297        |      NULL | 3:30 PM  |
|  1 |          1 | 01/20/13 | 6:00    |                              | Excavator   | 01E        |      7238 | 17:00    |
|  2 |          1 | 01/21/13 | 6:00    | Worked in Jefferson          | Excavator   | 01E        |      7238 | 17:00    |
|  3 |          1 | 01/22/13 | 6:00    | Worked in Jefferson          | Excavator   | 02E        |      7238 | 17:30    |
|  4 |          1 | 01/23/13 | 6:00    | Worked in Whispering Creek   | Skid Loader | 32SL       |      2338 | 18:30    |
|  5 |          1 | 01/24/13 | 8:00    | Worked in Hubbard            | Scraper     | 54C        |      9638 | 11:30    |
|  6 |          1 | 01/25/13 | 8:00    | Worked in Jefferson          | Dozer       | 4D         |       941 | 19:30    |
|  7 |          1 | 01/26/13 | 8:00    | Pushed Snow                  | Loader      | 950H       |       342 | 20:30    |
+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+

好的，所以我想看到的是，例如，日期以不同的值01/15/13出现两次，我想得到一个值，说在 id 8 的行中有 2:30 小时，然后得到另一个值，说在 id 为 9 的行中有 2:00 小时。如果可能的话，我想用一个查询来完成这个。timeIntimeOut

这是我获取一整天时间的查询：

SELECT `employeeID`, SEC_TO_TIME(SUM(TIME_TO_SEC(TIMEDIFF(`timeOut`, `timeIn`))))   AS `totalTime` FROM `timeRecords` WHERE   `date` = "01/15/13"  AND `employeeID` = 1 GROUP BY `employeeID`;
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2 回答 2

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如果我理解正确，你需要这个吗？

SELECT `employeeID`, TIMEDIFF(`timeOut`, `timeIn`)  AS `totalTime` FROM `timeRecords`;

您可以使用PDO query查询返回结果集作为关联数组数组的数据库。为了获得更好的性能，您可以使用PDO prepare/execute.

<?php
function getTimeByRow($connection) {
    $sql = "SELECT `employeeID`, TIMEDIFF(`timeOut`, `timeIn`)  AS `totalTime` FROM `timeRecords`";
    foreach ($connection->query($sql) as $row) {
        print $row['employeeID'] . "\t";
        print $row['totalTime'] . "\n";
    }
}
?>
于 2013-01-22T05:18:37.900 回答
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所以你想做这样的事情：

从 timeRecords 中选择 employeeID、date、TIMEDIFF(timeout, timein)，其中 date = x 和 employeeID = y

于 2013-01-22T05:19:37.767 回答