我正在尝试上 Python 课程，但发现讲师将其留给谷歌来教我们。我必须读取两个文本文件，解析它们，并将数据存储在字典中，以便将其用于比较和打印两个文本文件的结果。既然您知道我为什么要尝试做某事，那么我要做的就是打印一个数据列表，使其看起来对人眼可读。目前在打印时，我收到如下列表：
{0: ('Arthur', '3', '1'), 1: ('Lancelot', '0', '0'), 2: ('Robin', '0', '2'), 3: ('Arthur', '0', '3'), 4: ('Lancelot', '2', '0'), 5: ('Robin', '1', '2'),……
我希望它在控制台中像这样显示为每行映射数据的一个键值，像这样
{0: ('Arthur', '3', '1')
1: ('Lancelot', '0', '0')
2: ('Robin', '0', '2')
3: ('Arthur', '0', '3')
4: ('Lancelot', '2', '0')
5: ('Robin', '1', '2')
....}
显然，我不知道要在谷歌中找到正确的问题。我确信这很简单，例如格式化标志。这实际上不是作业的一部分，但我想学习如何做到这一点，因为稍后我将不得不为该程序的其他部分格式化输出。这是我作为输入读取的文本文件：
Arthur;3;1
Lancelot;0;0
Robin;0;2
Arthur;0;3
Lancelot;2;0
Robin;1;2
Robin;2;1
Lancelot;1;1
Galahad;0;1
a random person;0;3
Arthur;1;1
Galahad;1;1
Galahad;3;0
注意：我不必制作防弹代码，所以我没有。我不必考虑不良数据或任何类型的异常。我只需要让它处理这种类型的文本文件。
这是我的代码：
# readfile(string)
# Purpose: open a text file and iterate though the file, one line at a time.
# Input: string
# Returns: dictionary
def readResponses(filename):
mapIndex = 0 # used to append to dictionary rows.
for line in open(filename): # used to iterate through each txt file line.
if mapIndex < 1:# assign key and tuple data.
record = {mapIndex: parseForColon(line)}
mapIndex += 1
elif mapIndex > 0: # append key and tuple data
record.update({mapIndex: parseForColon(line)})
mapIndex += 1
return record
#def readQuestions():
# parseForColon(string)
# Purpose: Parse string data to assign appropriate data to three variables. Slices an input string one char
# qt-a-time until a delimiter is found. Delimiters are disregarded and a tuple is packed into a single variable.
# Input: String - The next line of text
# Returns: a packed tuple
# Called by readResponses(string)
def parseForColon(line): # This function iterates, releases memory, and is called anew from parent function.
string1, name, = line, "" # needed to receive text file line and slices of that string.
length = len (line)
count = 0
while count < length: # slice the string one char at a time until a delimiter is found.
if string1[count] == ';':
count += 1 # increment past the delimeter and assign next parameter.
question = string1[count]
count += 2 # increment past the next delimeter and assign last parameter.
answer = string1[count]
count += 1 #exceed length and break loop.
break
elif string1[count] != ';': # while delimeter not encountered, append first parameter one char at-a-time.
name += string1[count]
count += 1
data = name, question, answer
return data #return tuple.
#parse answers text file and save data to a dictionary.
answerMap = readResponses("responses.txt")
print answerMap
任何帮助，将不胜感激。我似乎从谷歌或其他人那里学到的东西比我在课堂上学到的更多，令人沮丧。