1

我有一个查询返回的结果类似于下面的创建表查询

create table #testresults
(
  pat_id int,
  fill_date date,
  script_end_date date,
  drug_class char(3),
  distinctDrugs int
)

pat_id 可以提供七种不同类别的药物。该列是在和的时间范围内可以给予distinctDrugs的不同药物的数量。运行查询的结果如下所示： pat_idfill_datescript_end_date在此处输入图像描述

每个pat_id都有许多不同fill_date的script_end_date时间段。这些不同的时间段具有不同的drug_class和distinctDrugs每行。这个例子的右边两列表示我需要什么：我需要在每一行，for eachfill_date和script_end_datethedrug_class和distinctDrugsfor each drug_class。我使用此查询将最右边的两列添加到我的基本视图

select distinct
 t.pat_id
,t.fill_date
,t.script_end_date
,t.drug_class
,t.distinctDrugs
,h3a.drug_class as h3aDrugClass
,h3a.distinctDrugs
from #temp as t
left join 
(
    select 
     pat_id
    ,fill_date
    ,script_end_date
    ,drug_class
    ,distinctDrugs
    from #temp 
    where drug_class='h3a'
) as h3a on h3a.pat_id=t.pat_id and h3a.fill_date between t.fill_date and t.script_end_date and t.drug_class !=h3a.drug_class
where h3a.drug_class is not null

对其余列执行此操作很容易drug_class，但这并不是很有效。有没有办法更简单地使用递归（或任何其他方式）？

编辑：这是我正在寻找的最终产品：

select distinct 
 f.pat_id
,f.fill_date
,f.script_end_date
,case when h3a.drug_class is null then 'H3A' else 'H3A' end as H3A
,isnull(h3a.distinctDrugs,0) as h3aCounts
,case when h4b.drug_class is null then 'H4B' else 'H4B' end as H4B
,isnull(h4b.distinctDrugs,0) as h4bCounts
,case when h6h.drug_class is null then 'H6H' else 'H6H' end  as H6H
,isnull(h6h.distinctDrugs,0) as h6hCounts
,case when h2s.drug_class is null then 'H2S' else 'H2S' end as H2S 
,isnull(h2s.distinctDrugs,0) as h2sCounts
,case when h2e.drug_class is null then 'H2E' else 'H2E' end  as H2E
,isnull(h2e.distinctDrugs,0) as h2eCounts
,case when h2f.drug_class is null then 'H2F' else 'H2F' end as H2F
,isnull(h2f.distinctDrugs,0) as h2fCounts
,case when j7c.drug_class is null then 'J7C' else 'J7C' end  as J7C
,isnull(j7c.distinctDrugs,0) as j7cCounts
from familyStrata as f
left join 
(
    select
     pat_id
    ,drug_class
    ,distinctDrugs
    ,fill_date
    from familyStrata 
    where drug_class='h3a'
) as h3a on h3a.pat_id=f.pat_id and h3a.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='h4b'
) as h4b on h4b.pat_id=f.pat_id and h4b.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='h6h'
) as h6h on h6h.pat_id=f.pat_id and h6h.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='h2f'
) as h2f on h2f.pat_id=f.pat_id and h2f.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='h2s'
) as h2s on h2s.pat_id=f.pat_id and h2s.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='h2e'
) as h2e on h2e.pat_id=f.pat_id and h2e.fill_date between f.fill_date and f.script_end_date
left join 
(
    select
     pat_id
    ,drug_class
    ,fill_date
    ,distinctDrugs
    from familyStrata
    where drug_class='j7c'
) as j7c on j7c.pat_id=f.pat_id and j7c.fill_date between f.fill_date and f.script_end_date

这实际上相当快，但绝不是远程优雅/可扩展的。结果集应如下所示： 在此处输入图像描述

您可以看到每个时间段内每种不同药物的 drug_class 和 distinctDrugs 的数量。现在，对于这个问题，还有比这更优雅的解决方案吗？

4

2 回答 2

0

在 SQL Server 中，您使用公用表表达式 (CTE) 进行递归查询。就是这样：

http://msdn.microsoft.com/en-gb/library/ms186243(v=sql.105).aspx

于 2013-01-21T16:31:53.220 回答
0

因此，递归并不是执行此操作的最佳方法。我解决了

select
 pat_id
,fill_date
,script_end_date
,'h3a' as h3a, coalesce(sum(case when drug_class='h3a' then distinctDrugs end),0) as h3aCounts
,'h4b' as h4b, coalesce(sum(case when drug_class='h4b' then distinctDrugs end),0) as h4bCounts
,'h6h' as h6h, coalesce(sum(case when drug_class='h6h' then distinctDrugs end),0) as h6hCounts
,'h2e' as h2e, coalesce(sum(case when drug_class='h2e' then distinctDrugs end),0) as h2eCounts
,'h3a' as h2f, coalesce(sum(case when drug_class='h2f' then distinctDrugs end),0) as h2fCounts
,'h3a' as h2s, coalesce(sum(case when drug_class='h2s' then distinctDrugs end),0) as h2sCounts
,'h3a' as j7c, coalesce(sum(case when drug_class='j7c' then distinctDrugs end),0) as j7cCounts
,row_number() over(order by pat_id) as rn
from x
group by pat_id,fill_date,script_end_date
)
于 2013-01-22T23:11:44.967 回答