0

我有这种查询:

SELECT COUNT( * ) 
FROM `reportinc` 
WHERE `Data/ora apertura` >=  '21/01/13 00:00:00' 
    AND `Data/ora apertura` <= '21/01/13 18:00:00'

从今天起,我必须在过去的 30 天内重复此查询。如何自动化?

而不是白天:21/01/13 我必须插入诸如 TODAY -1、TODAY -2 等之类的东西,但我自己指定了时间戳。

如何?

4

3 回答 3

0
 SELECT    TO_DAYS(NOW()) - TO_DAYS(your_table_column_name) <= 30;

或使用 DATEDIFF

mysql> SELECT DATEDIFF('1997-12-31 23:59:59','1997-12-30');
        -> 1
于 2013-01-21T15:32:15.780 回答
0

你可以使用BETWEEN

SELECT COUNT( * ) 
FROM `reportinc`
WHERE `Data/ora apertura` 
BETWEEN 
    CURRENT_DATE - INTERVAL 2 DAY 
AND 
    CURRENT_DATE - INTERVAL 1 DAY + '18:00:00'
于 2013-01-21T15:33:40.513 回答
0

像这样的东西:

WHERE `Data/ora apertura` >= CURRENT_DATE - INTERVAL 2 DAY
  AND `Data/ora apertura` <= CURRENT_DATE - INTERVAL 1 DAY
                                          + INTERVAL '18:00:00' HOUR_SECOND
于 2013-01-21T15:29:02.077 回答