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我在一个类中创建了一个 main() 方法来测试 XML 文件的构造。

public static void main(String[] args) {
    createXmlEmail();
}

这就是构建 XML 文件的方法。

private static void createXmlEmail() {
    XStream xstream = new XStream(new DomDriver());
    xstream.setMode(XStream.NO_REFERENCES);
    xstream.alias("email", EmailPojo.class);
    xstream.alias("recipient", Recipient.class);

    EmailPojo ep = new EmailPojo();

    List<Recipient> toRecipient = new ArrayList<Recipient>();
    toRecipient.add(new Recipient("user1@somecompany.com"));
    toRecipient.add(new Recipient("user2@somecompany.com"));

    List<Recipient> ccRecipient = new ArrayList<Recipient>();
    ccRecipient.add(new Recipient("user3@somecompany.com"));
    ccRecipient.add(new Recipient("user4@somecompany.com"));

    List<Recipient> bccRecipient = new ArrayList<Recipient>();
    bccRecipient.add(new Recipient("user5@somecompany.com"));
    bccRecipient.add(new Recipient("user6@somecompany.com"));

    ep.setTo(toRecipient);
    ep.setCc(ccRecipient);
    ep.setBcc(bccRecipient);
    ep.setSubject("subject test");
    ep.setBody("body test");

    String xml = xstream.toXML(ep);
    System.out.println(xml);
}

提到的 EmailPojo 和 Recipient 类定义为：

public static class EmailPojo {
        private List<Recipient> to;
        private List<Recipient> cc;
        private List<Recipient> bcc;
        private String subject;
        private String body;

        public List<Recipient> getTo() {
            return to;
        }

        public void setTo(List<Recipient> to) {
            this.to = to;
        }

        public List<Recipient> getCc() {
            return cc;
        }

        public void setCc(List<Recipient> cc) {
            this.cc = cc;
        }

        public List<Recipient> getBcc() {
            return bcc;
        }

        public void setBcc(List<Recipient> bcc) {
            this.bcc = bcc;
        }

        public String getSubject() {
            return subject;
        }

        public void setSubject(String subject) {
            this.subject = subject;
        }

        public String getBody() {
            return body;
        }

        public void setBody(String body) {
            this.body = body;
        }
    }


public static class Recipient {
    private String recipient;

    public Recipient(String recipient) {
        this.recipient = recipient;
    }

    public String getRecipient() {
        return recipient;
    }

    public void setRecipient(String recipient) {
        this.recipient = recipient;
    }
}

当我运行这个主类时，我没有收到任何错误或异常，输出是：

<email>
  <to>
    <recipient>
      <recipient>user1@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user2@company.com</recipient>
    </recipient>
  </to>
  <cc>
    <recipient>
      <recipient>user3@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user4@company.com</recipient>
    </recipient>
  </cc>
  <bcc>
    <recipient>
      <recipient>user5@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user6@company.com</recipient>
    </recipient>
  </bcc>
  <subject>subject test</subject>
  <body>body test</body>
</email>

但我希望它是这样的：

<email>
  <to>
    <recipient>user1@company.com</recipient>
    <recipient>user2@company.com</recipient>
  </to>
  <cc>
    <recipient>user3@company.com</recipient>
    <recipient>user4@company.com</recipient>
  </cc>
  <bcc>
    <recipient>user5@company.com</recipient>
    <recipient>user6@company.com</recipient>
  </bcc>
  <subject>subject test</subject>
  <body>body test</body>
</email>

我在这里想念什么？

提前致谢！

4

1 回答 1

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这是因为 Recipient 类具有属性接收者。如果您将收藏标记为@XStreamImplicit，则外部收件人标签将被消除。

请参阅隐式集合

于 2013-01-21T14:09:39.217 回答