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我想在不同表的两行之间减去：

我创建了一个view被调用的leave_taken和table被调用的leave_balance。

我想从两个表中得到这个结果：

leave_taken.COUNT(*) - leave_balance.balance

并分组leave_type_id_leave_type

两个表的代码

-----------------查看 Leave_Taken------------

CREATE ALGORITHM = UNDEFINED DEFINER=`1`@`localhost` SQL SECURITY DEFINER 
VIEW `leave_taken` 
AS 
   select 
     `leave`.`staff_leave_application_staff_id_staff` AS `staff_leave_application_staff_id_staff`,
     `leave`.`leave_type_id_leave_type` AS `leave_type_id_leave_type`,
     count(0) AS `COUNT(*)` 
   from 
   (
      `leave` 
      join `staff` on((`staff`.`id_staff` = `leave`.`staff_leave_application_staff_id_staff`))
   ) 
   where (`leave`.`active` = 1) 
   group by `leave`.`leave_type_id_leave_type`;

------表leave_balance----------

CREATE TABLE IF NOT EXISTS `leave_balance` (
  `id_leave_balance` int(11) NOT NULL AUTO_INCREMENT,
  `staff_id_staff` int(11) NOT NULL,
  `leave_type_id_leave_type` int(11) NOT NULL,
  `balance` int(3) NOT NULL,
  `date_added` date NOT NULL,
  PRIMARY KEY (`id_leave_balance`),
  UNIQUE KEY `id_leave_balance_UNIQUE` (`id_leave_balance`),
  KEY `fk_leave_balance_staff1` (`staff_id_staff`),
  KEY `fk_leave_balance_leave_type1` (`leave_type_id_leave_type`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

------- 餐桌休假 ----------

CREATE TABLE IF NOT EXISTS `leave` (
  `id_leave` int(11) NOT NULL AUTO_INCREMENT,
  `staff_leave_application_id_staff_leave_application` int(11) NOT NULL,
  `staff_leave_application_staff_id_staff` int(11) NOT NULL,
  `leave_type_id_leave_type` int(11) NOT NULL,
  `date` date NOT NULL,
  `active` int(11) NOT NULL DEFAULT '1',
  `date_updated` date NOT NULL,
  PRIMARY KEY (`id_leave`,`staff_leave_application_id_staff_leave_application`,`staff_leave_application_staff_id_staff`),
  KEY `fk_table1_leave_type1` (`leave_type_id_leave_type`),
  KEY `fk_table1_staff_leave_application1` (`staff_leave_application_id_staff_leave_application`,`staff_leave_application_staff_id_staff`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=32 ;
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1 回答 1

1

好吧，我仍然认为你没有提供足够的信息。拥有一些示例数据和您的预期输出（以表格格式）将非常有帮助。也就是说，我可能有一些你可以开始使用的东西。此查询查找所有员工，计算他们当前的休假（按类型分组），并根据休假类型确定其与余额之间的差异。看看它，更重要的是（也许）我在这里使用的 sqlfiddle，其中包含示例数据（对于确定这是否是您的数据的正确路径非常重要）。

SELECT
    staff.id_staff,
    staff.name,
    COUNT(`leave`.id_leave) AS leave_count,
    leave_balance.balance,
    (COUNT(`leave`.id_leave) - leave_balance.balance) AS leave_difference,
    `leave`.leave_type_id_leave_type AS leave_type
  FROM
    staff
    JOIN `leave` ON staff.id_staff = `leave`.staff_leave_application_staff_id_staff
    JOIN leave_balance ON
      (
        staff.id_staff = leave_balance.staff_id_staff
        AND `leave`.leave_type_id_leave_type = leave_balance.leave_type_id_leave_type
      )
  WHERE 
    `leave`.active = 1
  GROUP BY
    staff.id_staff, leave_type;

祝你好运！

于 2013-01-22T17:43:16.250 回答