mysql - MySQL在两个字母之间搜索

Question

我有一长串公司名称，但我只想要结果集只返回以字母 AE 开头的公司的结果。

那可能吗？

Answer 1

尝试使用LIKE

SELECT *
FROM   tableName
WHERE  CompanyName LIKE 'A%' OR
       CompanyName LIKE 'B%' OR
       CompanyName LIKE 'C%' OR
       CompanyName LIKE 'D%' OR
       CompanyName LIKE 'E%' 

或正则表达式

SELECT * 
FROM   tableName
WHERE  CompanyName REGEXP '^[A-E]';

• SQLFiddle Demo（两个查询）

其他）

• MySQL 正则表达式

Answer 2

您可以（也）使用简单的字符串比较来做到这一点；

SELECT *
FROM Companies 
WHERE CompanyName >= 'a'  
  AND CompanyName <  'f';  -- to be sure to get _all_ companies on 'E' 

简单的 SQLfiddle。

Answer 3

Company names starting with A, E using LEFT. If you need ending with then you can use RIGHT as well.

SELECT * 
FROM   YOURTABLE
WHERE  LEFT(CompanyName,1) IN ('A', 'E')
;

Answer 4

SELECT name FROM TABLE_NAME WHERE name BETWEEN 'a' AND 'e'

或者

SELECT Name FROM Employees WHERE Name REGEXP '^[A-E].*$'

Answer 5

SELECT * FROM mytable WHERE company_name < 'F';