保存从 WCF/web 服务接收到的 windows phone 中的数据。一段时间后可能会收到响应,因此如何处理这种情况。保存数据没问题,但是数据接收晚了怎么处理
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359 次
2 回答
0
您可以使用此代码(显示我项目中的代码):
public void sendPost(string postData, Action<MyResponse, Exception> callback, CreateResponse creater)
{
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(UrlRequest);
webRequest.Method = "POST";
webRequest.ContentType = "application/x-www-form-urlencoded";
webRequest.Accept = "application/json";
webRequest.AllowAutoRedirect = true;
webRequest.BeginGetRequestStream(new AsyncCallback(getRequestStreamCallback), new Request()
{
HttpRequest = webRequest,
PostData = postData,
Url = UrlRequest,
CallBack = callback,
Creater = creater
});
}
private void getRequestStreamCallback(IAsyncResult asynchronousResult)
{
var request = (Request)asynchronousResult.AsyncState;
// End the stream request operation
Stream postStream = request.HttpRequest.EndGetRequestStream(asynchronousResult);
byte[] byteArray = Encoding.UTF8.GetBytes(request.PostData);
// Add the post data to the web request
postStream.Write(byteArray, 0, byteArray.Length);
postStream.Close();
// Start the web request
request.HttpRequest.BeginGetResponse(new AsyncCallback(getResponseCallback), request);
}
private void getResponseCallback(IAsyncResult asynchronousResult)
{
var request = (Request)asynchronousResult.AsyncState;
try
{
HttpWebResponse response;
// End the get response operation
response = (HttpWebResponse)request.HttpRequest.EndGetResponse(asynchronousResult);
Stream streamResponse = response.GetResponseStream();
StreamReader streamReader = new StreamReader(streamResponse);
var myResponse = streamReader.ReadToEnd();
streamResponse.Close();
streamReader.Close();
response.Close();
MyResponse response_obj = request.Creater.CreateResponseObj();
using (MemoryStream stream = new MemoryStream(Encoding.Unicode.GetBytes(myResponse)))
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(response_obj.GetType());
response_obj = (GYResponse)serializer.ReadObject(stream);
if (request.CallBack != null)
{
request.CallBack.Invoke(response_obj, null);
}
}
}
catch (WebException e)
{
if (request.CallBack != null)
{
request.CallBack.Invoke(null, e);
}
}
}
public void getInfo(string uid, Action<MyResponse, Exception> callback)
{
CreateResponse creater = new CreateResponseGetInfo();
string model = "User";
string method = "getInfo";
Params parametrs = new Params();
parametrs.Uid = uid;
//create yor request
string request = getRequestString(model, method, parametrs, Atoken);
sendPost(request, callback, creater);
}
因此,您调用方法,该方法将请求发送到 Web 服务postRequester.getInfo(uid, ResponseHandler)
并使用委托来处理结果。
private void ResponseHandler(MyResponse result, Exception error)
{
if (error != null)
{
string err = error.Message;
return;
}
else
{
var infoResponse = result as ResponseGetInfo;
if (infoResponse != null)
{
//result processing..
}
}
}
于 2013-01-21T05:18:36.250 回答
0
您在 Windows Phone 应用程序中发出的所有 Web 请求都是异步的。这意味着,您从您的应用程序发出一个 Web 请求并附加一个处理程序来处理响应时的响应。在响应处理程序中,您必须处理响应并使用它做任何您想做的事情。
于 2013-01-21T06:19:23.210 回答