13

我有一个 Play 2.0.1 应用程序，我想使用托管在其他域上的 Javascript 来调用它。我的 Javascript 调用失败：

Origin http://mydomain.com is not allowed by Access-Control-Allow-Origin.

我找到了许多如何在 Play 1 中设置正确的 HTTP 标头的示例，但没有找到 Play 2.0.1 的任何内容。阅读文档（http://www.playframework.org/documentation/2.0.2/JavaResponse）后，我尝试了以下操作以使工作正常：

public static Result myJsonWebService() {
  ...
  response().setHeader("Access-Control-Allow-Origin", "*");
  return ok(toJson(jsonObject));
}

但我的 JS Web 服务调用仍然失败。

我需要做什么才能使它正常工作？

4

4 回答 4

14

仅对于 Scala 人来说，这是我目前正在使用的实现：

import play.api.mvc._
import scala.concurrent._
import play.api.http.HeaderNames._

/**
 * Action decorator that provide CORS support
 *
 * @author Giovanni Costagliola, Nick McCready
 */
case class WithCors(httpVerbs: String*)(action: EssentialAction) extends EssentialAction with Results {
    def apply(request: RequestHeader) = {
        implicit val executionContext: ExecutionContext = play.api.libs.concurrent.Execution.defaultContext
        val origin = request.headers.get(ORIGIN).getOrElse("*")
        if (request.method == "OPTIONS") { // preflight
            val corsAction = Action {
                request =>
                    Ok("").withHeaders(
                        ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
                        ACCESS_CONTROL_ALLOW_METHODS -> (httpVerbs.toSet + "OPTIONS").mkString(", "),
                        ACCESS_CONTROL_MAX_AGE -> "3600",
                        ACCESS_CONTROL_ALLOW_HEADERS ->  s"$ORIGIN, X-Requested-With, $CONTENT_TYPE, $ACCEPT, $AUTHORIZATION, X-Auth-Token",
                        ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true")
            }
            corsAction(request)
        } else { // actual request
            action(request).map(res => res.withHeaders(
                ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
                ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
            ))
        }
    }
}

要使用它，只需按以下方式装饰您的操作：

def myAction = WithCors("GET", "POST") {
  Action { request =>
    ???
  }
}
于 2013-11-11T13:44:24.710 回答
11

这里有一些背景信息...

  • 1) http://www.html5rocks.com/en/tutorials/cors/ - 请注意，您需要阅读有关“不那么简单的请求”的内容，因为 JSON 属于此类。
  • 2）http://stackoverflow.com/questions/9613210/cors-access-control-allow-origin-despite-correct-headers?rq=1
  • 3) http://caniuse.com/#search=cors - 详细介绍支持 CORS 的浏览器
  • 4）http://stackoverflow.com/questions/10748537/access-control-allow-origin-on-playframework（玩1不玩2）

所以这是我实现的：

由于不是那么简单的请求（参见上面的 1）进行飞行前调用，您需要将以下内容添加到路由文件中：

POST /url_to_json_webservice        controllers.myJsonWebServices.myJsonWebService
OPTIONS /url_to_json_webservice     controllers.myJsonWebServices.checkPreFlight

然后在您的控制器中设置以下方法：

public static Result checkPreFlight() {
    response().setHeader("Access-Control-Allow-Origin", "*");       // Need to add the correct domain in here!!
    response().setHeader("Access-Control-Allow-Methods", "POST");   // Only allow POST
    response().setHeader("Access-Control-Max-Age", "300");          // Cache response for 5 minutes
    response().setHeader("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");         // Ensure this header is also allowed!  
    return ok();
}

注意我可能在这里设置了比需要更多的标题，所以请检查你需要哪些！

还要记住将以下内容添加到返回实际 JSON 结果的控制器方法的末尾（如我上面的问题）：

public static Result myJsonWebService() {
  ...
  response().setHeader("Access-Control-Allow-Origin", "*");
  return ok(toJson(jsonObject));
}
于 2013-01-21T10:55:10.587 回答
3

一个很好的方法是扩展动作：

package actions;

import play.*;
import play.mvc.*;
import play.mvc.Http.Context;
import play.mvc.Http.Response;

public class CorsAction extends Action.Simple {

public Result call(Context context) throws Throwable{
    Response response = context.response();
    response.setHeader("Access-Control-Allow-Origin", "*");

    //Handle preflight requests
    if(context.request().method().equals("OPTIONS")) {
        response.setHeader("Access-Control-Allow-Methods", "POST, GET, OPTIONS, PUT, DELETE");
        response.setHeader("Access-Control-Max-Age", "3600");
        response.setHeader("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept, Authorization, X-Auth-Token");
        response.setHeader("Access-Control-Allow-Credentials", "true");

        return ok();
    }

    response.setHeader("Access-Control-Allow-Headers","X-Requested-With, Content-Type, X-Auth-Token");
    return delegate.call(context);
}

}

然后在你的控制器中添加这一行：

@With(CorsAction.class)

然后所有 ok() 请求都将响应上述标头。

于 2013-09-30T08:52:02.753 回答
1

实现为 Scala 过滤器（播放 2.2.x）：

import scala.concurrent.ExecutionContext.Implicits.global
import play.api.mvc._
import play.api.mvc.Results._
import play.api.http.HeaderNames._

object Cors extends Filter {
  def apply(next: (RequestHeader) => Future[SimpleResult])(request: RequestHeader): Future[SimpleResult] = {
    val origin = request.headers.get(ORIGIN).getOrElse("*")
    if (request.method == "OPTIONS") {
      val response = Ok.withHeaders(
        ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
        ACCESS_CONTROL_ALLOW_METHODS -> "POST, GET, OPTIONS, PUT, DELETE",
        ACCESS_CONTROL_MAX_AGE -> "3600",
        ACCESS_CONTROL_ALLOW_HEADERS -> s"$ORIGIN, X-Requested-With, $CONTENT_TYPE, $ACCEPT, $AUTHORIZATION, X-Auth-Token",
        ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
      )
      Future.successful(response)
    } else {
      next(request).map {
        res => res.withHeaders(
          ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
          ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
        )
      }
    }
  }
}

object Global extends WithFilters(Cors) {...}
于 2014-03-26T18:38:05.010 回答