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我首先使用以下查询计算数据库中男性和女性的百分比:

SELECT sum(case when `gender` = 'M' then 1 else 0 end) as male
     , sum(case when `gender` = 'F' then 1 else 0 end) as female
FROM userinfo 
WHERE id in (10,1,5)

然后在php中我计算百分比。但我想知道,有没有办法直接从查询中获取百分比?

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SELECT sum(case when `gender` = 'M' then 1 else 0 end) as male
     , 100*sum(case when `gender` = 'M' then 1 else 0 end)/count(*) as malepct
     , sum(case when `gender` = 'F' then 1 else 0 end) as female
     , 100*sum(case when `gender` = 'F' then 1 else 0 end)/count(*) as femalepct
FROM userinfo 
WHERE id in (10,1,5)

...假设您没有在空行集上运行它(除以零)

如果您想用 -1 替换无效(除以零)值,请使用

if(ifnull(count(*),0)>0,100*sum(case when `gender` = 'M' then 1 else 0 end)/count(*),-1) as malepct
于 2013-01-20T20:45:17.187 回答