var $fileVideo = $("<form action='videoupload.php' method='post' enctype='multipart/form-data' target='upload_target_video' onsubmit='return videoClickHandler(this);' class='videouploadform' >" +
"Video File: <input name='fileVideo' type='file' class='fileVideo' /></label>" +
"<input type='submit' name='submitVideoBtn' class='sbtnvideo' value='Upload' /></label>" +
"<p class='listVideo' align='left'></p>" +
"<iframe class='upload_target_video' name='upload_target_video' src='/' style='width:0px;height:0px;border:0px;solid;#fff;'></iframe></form>");
现在下面我有一个 jquery 代码,当文件完成上传时触发。
function htmlEncode(value) { return $('<div/>').text(value).html(); }
function stopVideoUpload(success, videofilename){
var result = '';
videocounter++;
if (success == 1){
result = '<span class="videomsg'+videocounter+'">The file was uploaded successfully</span>';
$('.listVideo').eq(window.lastUploadVideoIndex).append('<div>' + htmlEncode(videofilename));
}
return true;
}
下面是它上传文件的代码,然后使用 javascriptid
从数据库中接收文件名和文件名,并将其发布回上面的 javascript 函数以显示信息:
move_uploaded_file($_FILES["fileVideo"]["tmp_name"],
"VideoFiles/" . $_FILES["fileVideo"]["name"]);
$result = 1;
$videosql = "INSERT INTO Video (VideoFile)
VALUES (?)";
if (!$insert = $mysqli->prepare($videosql)) {
// Handle errors with prepare operation here
}
//Assign the variable
$vid = 'VideoFiles/'.$_FILES['fileVideo']['name'];
//Dont pass data directly to bind_param store it in a variable
$insert->bind_param("s",$vid);
$insert->execute();
$id = $mysqli->insert_id;
if ($insert->errno) {
// Handle query error here
}
$insert->close();
}else{
echo "Upload was not successful";
}
<script language="javascript" type="text/javascript">
window.top.stopVideoUpload(<?php echo $result; ?>,'<?php echo $id . $_FILES['fileVideo']['name'] ?>');
</script>
因此,如果上传文件VideoFiles/tulips.png
,那么在 db 中它看起来像这样,例如:
视频表:
ImageId VideoFile
23 VideoFiles/tulips.mp4
所以在上面的 javascript 函数中它显示了这个:
23ImageFile/tulips.mp4
我的问题是,我希望$id
或如上例所示23
显示为隐藏的输入值。但我的问题是如何做到这一点?
更新:
function htmlEncode(value) { return $('<div/>').text(value).html(); }
function stopVideoUpload(success, videofilename, videoID){
var result = '';
videocounter++;
if (success == 1){
result = '<span class="videomsg'+videocounter+'">The file was uploaded successfully</span>';
$('.listVideo').eq(window.lastUploadVideoIndex).append('<input type="hidden" name="vidid" value="videoID" />');
$('.listVideo').eq(window.lastUploadVideoIndex).append('<div>' + htmlEncode(videofilename));
}
return true;
}
…………
move_uploaded_file($_FILES["fileVideo"]["tmp_name"],
"VideoFiles/" . $_FILES["fileVideo"]["name"]);
$result = 1;
$videosql = "INSERT INTO Video (VideoFile)
VALUES (?)";
if (!$insert = $mysqli->prepare($videosql)) {
// Handle errors with prepare operation here
}
//Assign the variable
$vid = 'VideoFiles/'.$_FILES['fileVideo']['name'];
//Dont pass data directly to bind_param store it in a variable
$insert->bind_param("s",$vid);
$insert->execute();
$id = $mysqli->insert_id;
if ($insert->errno) {
// Handle query error here
}
$insert->close();
}else{
echo "Upload was not successful";
}
<script language="javascript" type="text/javascript">
window.top.stopVideoUpload(<?php echo $result; ?>,'<?php echo $id; ?>','<?php echo $_FILES['fileVideo']['name']; ?>');
</script>