php - PHP 模式搜索

Question

我试图在文件中搜索 nn/nnnnnn/nn..

我有这个

if (preg_match_all("([0-9]{6})", $file, $out)) {
echo "Match was found <br />";
print_r($out);

它处理中心 6 个数字，但我如何让它搜索整个模式？当我必须将搜索字符串添加在一起时，我有点困惑。我知道我必须执行以下操作

([0-9]{2}) 和 / 和 ([0-9]{6}) 和 / 和 ([0-9]{2})

如何将搜索字符串添加为一个？在此先感谢干杯垫

Answer 1

你也可以用\d一个数字代替：

preg_match_all("#(\d{2})/(\d{6})/(\d{2})#", $string, $matches);
print_r($matches);

Answer 2

你有没有尝试过：

preg_match_all("/([0-9]{2})\/([0-9]{6})\/([0-9]{2})/")

例如，如果搜索12/123456/12，它将输出：

Array
(
    [0] => Array
        (
            [0] => 12/123456/12
        )

    [1] => Array
        (
            [0] => 12
        )

    [2] => Array
        (
            [0] => 123456
        )

    [3] => Array
        (
            [0] => 12
        )

)

Answer 3

试试这个#(\d{2})/(\d{6})/(\d{2})#：

$file = '23/334324/23';
if (preg_match_all("#(\d{2})/(\d{6})/(\d{2})#", $file, $out)) {
    echo "Match was found <br />";
    print_r($out);
}

回报：

Array
(
    [0] => Array
        (
            [0] => 23/334324/23
        )

    [1] => Array
        (
            [0] => 23
        )

    [2] => Array
        (
            [0] => 334324
        )

    [3] => Array
        (
            [0] => 23
        )

)

Answer 4

如何使用#([0-9]{2})/([0-9]{6})/([0-9]{2})#：

if(preg_match_all("#([0-9]{2})/([0-9]{6})/([0-9]{2})#", $file, $out)) 
{
    echo "Match was found <br />";
    print_r($out);
}