scala - 使用工厂作为函数文字实例化 scala 类型

Question

鉴于以下对先前在此处发布的问题的回答，我将如何更改 fac 函数以采用构造函数参数？

class BalanceActor[T <: Actor](val fac: () => T) extends Actor {
  val workers: Int = 10

  private lazy val actors = new Array[T](workers)

  override def start() = {
    for (i <- 0 to (workers - 1)) {
      actors(i) = fac() //use the factory method to instantiate a T
      actors(i).start
    }
    super.start()
  }
}

Answer 1

对于一个String论点：

class BalanceActor[T <: Actor](val fac: String => T) extends Actor ...

对于一个A论点：

class BalanceActor[A, T <: Actor](val fac: A => T) extends Actor ...